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Ilia_Sergeevich [38]
3 years ago
6

The answers..............................plz and thx

Mathematics
1 answer:
kati45 [8]3 years ago
5 0

Answer:x=6

Step-by-step explanation:

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Brad drives 527 miles on 17 gallons. How many miles does Brad drive on one gallon?
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31 miles per gallon
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The is the mean score ? A.25.5 B.26 C.
pentagon [3]
So to find the mean you add up all the numbers (or the exam scores) which will get you 212 then you take the number and divide it by the total numbers in the set (how many numbers did you add up?)

212 divided by 8 is 26.5 which would be C. I hope this helps!
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3 years ago
HELP NOW II WILL GIVE YOU 30 POINTS
Alex

Answer:

1; -11+ 26 =15

2: 2- (-3) =5

3: 10+ (-4) = 7

4: 11 + -8 =3

5: -2 + 3 =1

6:  8 - 12 = -4

Step-by-step explanation:

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3 years ago
Choose the correct simplification of (7x^3y^3)^2. (5 points) 100 POINTS GIVING BRAINLIEST FOR GOOD EXPLANATION
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Answer:

Option C

Step-by-step explanation:

(7x^3y^3)^2

= (7)^2 * (x^3)^2 * (y^3)^2

= 49 * x^(3*2) * y^(3*2)

= 49x^6y^6

You have to distribute the terms in "7x^3 * y^3" each to the power of 2

(7)^2 * (x^3)^2 * (y^3)^2

Now you can apply the rule "(x^a)^b = x^a*b" and further simplify the expression

4 0
3 years ago
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Solve: In 2x + In 2 = 0<br> DONE
pychu [463]

Answer:

x=\frac{1}{4}

Step-by-step explanation:

We can use some logarithmic rules to solve this easily.

<em>Note: Ln means Log_e</em>

<em />

Now, lets start with the equation:

ln(2x) + ln(2) = 0\\ln(2x) = -ln(2)

Writing left side with logarithmic base e, we have:

Log_{e}(2x) = -ln(2)

We can now use the property shown below to make this into exponential form:

Log_{a}b=x\\means\\a^x=b

So, we write:

Log_{e}(2x) = -ln(2)\\e^{-ln(2)}=2x

We recognize another property of exponentials:

a^{bc}=(a^{b})^{c}

So, we write:

e^{-ln(2)}=2x\\(e^{ln(2)})^{-1}=2x

Also, another property of natural logarithms is:

e^{(ln(a))}=a

Now, we simplify:

(e^{ln(2)})^{-1}=2x\\(2)^{-1}=2x\\\frac{1}{2}=2x\\x=\frac{\frac{1}{2}}{2}\\x=\frac{1}{4}

This is the answer.

7 0
3 years ago
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