Simplity (4.5)(5)(-2)<br> O45<br> 045<br> 0-45<br> -45

A rectangular skate park is 60 yards long and 50 yards wide

lawyer [7]

It is unclear what you want to do, but in the case where they give you the length and the width, it is most likely they are asking for either area or perimeter. For Area, it is length times width.
A = l x w
A = 60 yards x 50 yards
A = 3000 square yards.
For Perimeter of the rectangle, it is 2 of the lengths plus 2 of the widths.
P = 2 ( 60 yards ) + 2 ( 50 yards )
P = 120 yards + 100 yards
P = 220 yards
I hope this helps :-)

4 0

3 years ago

Need help with this (1)

attashe74 [19]

The answer, I think, is 7r/s

4 0

2 years ago

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an oil company drilled several walls.fifty wells, or 25%,produced oil.what was the total number of wells that were drilled

Phantasy [73]

25% is equal to 100/25=1/4

We can substitute this into an equation to get the total number of wells where n can be equal to the total number of wells.

1/4*n=50
n/4=50
n=50*4
n=200

The total number of wells that were drilled was 200.

6 0

2 years ago

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Find the inverse function for f(x)=sqrt2x-6 picture below

Olenka [21]

Answer:

y = (x^2 + 6) / 2

Step-by-step explanation:

Original function: $\sqrt{2x - 6}$

To find the inverse of a function we have to switch the x and y values and solve for y again

x = sqrt (2y-6)

To get rid of a square root we square the square root so:

x^2 = 2y-6

Add 6

x^2 + 6 = 2y

Divide by 2

y = (x^2 + 6) / 2

6 0

3 years ago

Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to

RUDIKE [14]

Answer:

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

$\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75$

And for the margin of error we have the following estimation:

$ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

$\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75$

And for the margin of error we have the following estimation:

$ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62$

5 0

3 years ago

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