Sinx =8/40
in order to solve this you would have to use the inverse which would be Sin^-1(8/40) giving you 11.5
Answer:
x>11 is the solution to both equations.
Step-by-step explanation:
I apologize for late response I've been busy lately. Anyways here ya go! :
From what I understand it wants us to solve "9x-4>95" so that's what I'll do.
add 4 to each side
9x>99
divide each side by 9
x>11 is the solution to 9x-4>95
For 4x+10>54
subtract 10 from each side
4x>44
divide each side by 4
x>11 is the solution to 4x+10>54
Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus
First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°.
Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.
For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.



Similarly, we have



Now, to find the lengths of the diagonals,


So, the lengths of the diagonals are 10 and 10√3.
Answer: 10 and 10√3 units
X+30+70=180
x+100=180. -100 both sides
x=80
|x=80° |
The sides of the triangle are 3x, 4x and 5x
3x + 4x + 5x = 90
12x = 90
x = 90/12
x = 7.5
first side = 3x = 3 * 7.5 = 22.5 cm
second side = 4x = 4 * 7.5 = 30 cm
third side = 5x = 5*7.5 = 37.5 cm