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Monica [59]
2 years ago
13

As the office purchasing manager you have to buy printer paper. Your last

Mathematics
1 answer:
bixtya [17]2 years ago
3 0

Answer:

a/1/$400

Step-by-step explanation:

240 divided by 12=20

20x10x2=$400

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50 points
Lana71 [14]
Sinx =8/40
in order to solve this you would have to use the inverse which would be Sin^-1(8/40) giving you 11.5
3 0
3 years ago
Part 7 math work 10th-grade work
Irina-Kira [14]

Answer:

x>11 is the solution to both equations.

Step-by-step explanation:

I apologize for late response I've been busy lately. Anyways here ya go! :

From what I understand it wants us to solve "9x-4>95" so that's what I'll do.

add 4 to each side

9x>99

divide each side by 9

x>11 is the solution to 9x-4>95

For 4x+10>54

subtract 10 from each side

4x>44

divide each side by 4

x>11 is the solution to 4x+10>54

3 0
3 years ago
A rhombus ABCD has AB = 10 and m∠A = 60°. Find the lengths of the diagonals of ABCD.
melisa1 [442]
Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus

First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°. 

Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.

For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.

\overline{OB}:\overline{AB} = 1:2
\overline {OB}:10 = 1:2
\overline{OB} = \frac{1}{2}(10) = 5

Similarly, we have

\overline{AO}:\overline{AB} = \sqrt{3}:2
\overline {AO}:10 = \sqrt{3}:2
\overline{AO} = \frac{\sqrt{3}}{2}(10) = 5\sqrt{3}

Now, to find the lengths of the diagonals, 

\overline{AD} = 2(\overline{AO}) = 10\sqrt{3}
\overline{BC} = 2(\overline{OB}) = 10

So, the lengths of the diagonals are 10 and 10√3.

Answer: 10 and 10√3 units

8 0
3 years ago
What is the value of x?<br><br><br><br> Enter your answer in the box.<br> |x = °|
Serga [27]
X+30+70=180
x+100=180. -100 both sides
x=80

|x=80° |
8 0
3 years ago
The sides of a triangle are in the ratio 3 : 4 : 5. What is the length of each side if the perimeter of the triangle is 90 cm
svet-max [94.6K]
The sides of the triangle are 3x, 4x and 5x

3x + 4x + 5x = 90
12x = 90
x = 90/12
x = 7.5

first side = 3x = 3 * 7.5 = 22.5 cm
second side = 4x = 4 * 7.5 = 30 cm
third side = 5x = 5*7.5 = 37.5 cm
7 0
3 years ago
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