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3 years ago

Solve the equation. 89=x+1/3(7)

2 answers:

5 0

Multiply both sides by 3
so it should look like this:
3x+7=267
now subtract 7 from each side so now it should look like this
3x=260
Now divide each side by 3
and you will get

x=260/3

sesenic [268]3 years ago

5 0

X= 260/3...............................

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X^2+25 A.(x+5)(x+5) B.(x+5)(x-5) C.(x-5)(x/5) D.prime

adell [148]

It’s prime because none of the other answers work.

8 0

3 years ago

A baby bird jumps from a tree branch and flutters to the ground. The function "f" models the bird's height (in meters) above the

AURORKA [14]

The answer to this question will depend on the function f itself. Basically you will find the height in meters above the ground of the bird when it jumped when the time t=0s. This is substsitute every t in the function for a value of zero and that way you will get the bird's height at the time it jumped. If you were given a graph for this function, you can find the y-intercept of the graph and that will be the answer as well. The question could be written like this:

A baby bird jumps from a tree branch and flutters to the ground. The function " $f(t)-4.9t^{2}+25$ " models the bird's height (in meters) above the ground as a function of time (in seconds) after jumping. What is bird's height above the ground when it jumped.

Answer:

25m

Step-by-step explanation:

Once your function is given, you can substitute t=0 since 0s is the time measured at the moment the bird jumped. So our function will be:

$f(0)=-4.9(0)^2+25$

$f(0)=25m$

So the height of the bird above the ground when it jumped is 25m in this particular function.

8 0

3 years ago

PLEASE HELP/ANSWER! From 1980 to 1990, Lior’s weight increased by 25%. If his weight was k kilograms in 1990, what was it in 198

Elena-2011 [213]

The weight in 1980 is $\frac{4k}{5}$ kilograms

Solution:

From 1980 to 1990, Lior’s weight increased by 25%

His weight is "k" kilograms in 1990

To find: weight in 1980

This is a percentage increase problem

Let "x" be the weight in kilograms in 1980

The percentage increase is given by formula:

$\text{Percentage increase } = \frac{\text{Final value - initial value}}{\text{initial value}} \times 100$

Here,

Initial value in 1980 = x

Final value in 1990 = k

Percentage increase = 25 %

Substituting the values in formula,

$25 = \frac{k-x}{x} \times 100\\\\25x = 100(k-x)\\\\x = 4(k-x)\\\\x = 4k - 4x\\\\5x = 4k\\\\x = \frac{4k}{5}$

Thus the weight in kilograms in 1980 is $\frac{4k}{5}$

7 0

3 years ago

Select the correct answer.

GREYUIT [131]

I don’t know
Igditditditd

4 0

2 years ago

Carla is age 32. how many quarters of coverage does she need to be fully insured

never [62]

According to my research, And I would take this with a grain of salt since I am not a insurance rep . You can earn up to four quarters of coverage each year. In order to be fully insured for Social Security Disability purposes, you must have earned at least one quarter of coverage per year for each year since you turned 21 years old. A minimum of six quarters of coverage is needed to be fully insured at any age so maybe Six quarters, at least according to SSD .
Hope I helped or shed some light !.

7 0

3 years ago