What are the possible values of x in -11x^2 + 2x = 10?

1 answer:

8 0

-11x² + 2x = 10
-11x² + 2x - 10 = 10 - 10
-11x² + 2x - 10 = 0
x = -(2) +/- √((2)² - 4(-11)(-10))
 2(-11)
x = -2 +/- √(4 - 440)
 -22
x = -2 +/- √(-436)
 -22
x = -2 +/- 2i√(109)
 -22
x = -2 + 2i√(109) x = -2 - 2i√(109)
 -22 -22
x = ¹/₁₁ - ¹/₁₁i√(109) x = ¹/₁₁ + ¹/₁₁i√(109)

You might be interested in

PLSSS HELP ME ON THIS

stiks02 [169]

1. True
2. False
3. True
When ordered for location 1, the values are 34,52,85,86,100 with the median is 85 because it is in the middle of the other values. True

The range of location 2 is from 19 to 65 base don data shown, False

The median for location 2 is (20,29) which is smaller than the 85 for location 1 so location 1 had more participants if based on the median measurement. True

3 0

4 years ago

Help please thank you

yarga [219]

X = 400!
Have a goody day:)

8 0

3 years ago

Laun

arlik [135]

Answer: 16.67% for question 1

83.33% for question 2

Step-by-step explanation:

1/6 as a percent is 16.67% because the is only 1 correct number

5/6 as a percent is 83.33% because there is 5 wrong numbers

3 0

3 years ago

Each pound of food C contains 6 ounces of ingredient P and 3 ounces of ingredient Q. Each pound of food D contains 4.5 ounces of

GuDViN [60]

So hmm the food C = 6p + 3q and the food D = 4.5p + 1.5q

now, if we check how much is the ratios of C/D for each component, then, mixture M = 144p + 60q, must contain the same ratio for each "p" and "q" component

$\bf \textit{ratio of "p"}\implies \cfrac{6}{4.5}\implies \cfrac{4}{3}
\\\\\\
\textit{ratio of "q"}\implies \cfrac{3}{1.5}\implies \cfrac{2}{1}$

so, if we divide the 144p by 4+3, or 7 even pieces, 4 must belong to food C and 3 to food D, retaining the ratio of 4/3

and we do the same for 60q, we divide it in 2+1 or 3 even pieces, but that one is very clear, 2 must belong to food C and 1 to food D, 60/3 is clear ends up with a ratio of 40 and 20

now the "p" part... ends up as $\bf \cfrac{144}{7}\cdot 4\qquad and\qquad \cfrac{144}{7}\cdot 3\implies \cfrac{576}{7}\qquad and\qquad \cfrac{432}{7}$

that's what I see it, as the ratio of 4/3 and 2/1 being retained in the mixture M

7 0

3 years ago

Solve x + 3y = 9. 3x – 3y = –13

Sloan [31]

$Question \ 1) \ x + 3y = 9$

$
x=9-3y
 
$ $|Subtract \ 3y \ from \ both \ sides|$

$Question \ 2) \ 3x - 3y = -13$

$
3(x-y)=-13
 
$ $|Factor \ out \ the \ common \ term \ 3|$

$x-y= \dfrac{13}{3}$ $|Divide \ both \ sides \ by \ 3|$

$x=- \dfrac{13}{3}+y$ $|Add \ y \ to \ both \ sides|$

$x=y- \dfrac{13}{3}$ $|Regroup \ terms|$

7 0

3 years ago