i will fill the boxes from top down
4(-2)-5=-13
4(1)-5=-1
4(2)-5=3
4(3)-5=7
A(-4, -1)
B(-3, -3)
C(0, 2)
First, you have to find the moment of inertia along the x and y axes. Constant density is denoted as k.


Then, the radii of gyration for
x = √[I_x/m]
y = [I_y/m]
where m = k(15-4)² = 121k. Then,
x = y = [4880.33k/121k] = 40.33
I hope I was able to help you. Have a good day.
So you can use substitution...which is where you have Y all alone on one side of your equation and then plug it in to the other equation...2x-5=-3x+10 and you.solve for X. So x= 3. Then plug 3 into one of the original equations... Y=2(3)+5. So Y= 11.
i calculated this problem and it's just 46.656