First we need to know what number 2*5*7 gives us. That's the same as 10*7=70. So the question is asking how many multiples of 70 are between 1 and 700. Let's list them:
70
140
210
280
350
420
490
560
630
700
So there are 10 integers from 1 to 700 that are divisible by 2, 5, and 7.
<u>Answer</u>
D.25x2 – 36
<u>Explanation</u>
A. x² – 16x + 64
product = 64
sum = -16
factors: -8 and -8
x² – 16x + 64 = x² - 8x - 8x + 64
= x(x - 8) - 8(x - 8)
= (x - 8)(x-8) = (x-8)² ⇒ Not a difference of squares
B.x² + 4 = (x² + 2²) ⇒ Not a difference of squares
C.9x² – x – 36
product = - 324
sum = -1
Factors: none
9x² – x – 36 ⇒ Has no perfect roots.
D.25x² – 36
25x² – 36 = (5x)² - 6² ⇒ This is the difference of squares.
Answer:
A. 9A² - 16B²
Step-by-step explanation:
(3A + 4B)(3A - 4B)
Distribute:
3A(3A - 4B)
4B(3A - 4B)
Multiply:
3A(3A - 4B)
3A(3A) + 3A(-4B)
9A² - 12AB
4B(3A - 4B)
4B(3A) + 4B(-4B)
12AB - 16B²
Combine like terms:
9A² - 12AB + 12AB - 16B² <== -12AB + 12AB cancels out
9A² - 16B²
Therefore, our final answer is 9A² - 16B²
Hope this helps!
Answer:1
Step-by-step explanation:
4% x 20 patients= 1 patient
