Question

Write the first ten terms of a sequence whose first term is -10 and whose common difference is -2.

Answer 1

Problem:

Write the first ten terms of a sequence whose first term is -10 and whose common difference is -2.

Solution:

$- 10 - ( - 2) = \boxed{ - 8}$

$- 8 - ( - 2) = \boxed{ - 6}$

$- 6 - ( - 2) = \boxed{ - 4}$

$- 4 - ( - 2) = \boxed{ - 2}$

$- 2 - ( - 2) = \boxed{0}$

$0 - ( - 2) = \boxed{2}$

$2 - ( - 2) = \boxed{4}$

$4 - ( - 2) = \boxed{6}$

$6 - ( - 2) = \boxed{8}$

Answer:

-10, -8, -6, -4, -2, 0, 2, 4, 6, 8

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