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3 years ago

(Middle school math) I just need to know the probabilities for letter a. Thank you.

Mathematics

2 answers:

Varvara68 [4.7K]3 years ago

6 0

The answer to the question is A

lisov135 [29]3 years ago

4 0

Answer:

use a tree diagram to get a visual representation over it then calculate you're probability.

You might be interested in

Using the Factor Theorem, which of the polynomial functions has the zeros 2, radical 3 , and negative radical 3 ?

Alja [10]

Using the factor theorem, it is found that the polynomial is:

$f(x) = x^3 - 2x^2 - 3x + 6$

Given by the first option

---------------------------

Given a polynomial f(x), this polynomial has roots $x_{1}, x_{2}, x_{n}$ using the factor theorem it can be written as: $a(x - x_{1})*(x - x_{2})*...*(x-x_n)$ , in which a is the leading coefficient.

---------------------------

In this question:

$x_1 = 2$
$x_2 = \sqrt{3}$
$x_3 = -\sqrt{3}$
By the options, leading coefficient $a = 1$

Thus:

$f(x) = (x - 2)(x - \sqrt{3})(x + \sqrt{3})$

$f(x) = (x - 2)(x^2 - 3)$

$f(x) = x^3 -2x^2 - 3x + 6$

Which is the polynomial.

A similar problem is given that: brainly.com/question/4786502

5 0

3 years ago

Some transportation experts claim that it is the variability of speeds, rather than the level of speeds, that is a critical fact

scZoUnD [109]

Answer:

Explained below.

Step-by-step explanation:

The claim made by an expert is that driving conditions are dangerous if the variance of speeds exceeds 75 (mph)².

(1)

The hypothesis for both the test can be defined as:

H₀: The variance of speeds does not exceeds 75 (mph)², i.e. σ² ≤ 75.

Hₐ: The variance of speeds exceeds 75 (mph)², i.e. σ² > 75.

(2)

A Chi-square test will be used to perform the test.

The significance level of the test is, α = 0.05.

The degrees of freedom of the test is,

df = n - 1 = 55 - 1 = 54

Compute the critical value as follows:

$\chi^{2}_{\alpha, (n-1)}=\chi^{2}_{0.05, 54}=72.153$

Decision rule:

If the test statistic value is more than the critical value then the null hypothesis will be rejected and vice-versa.

(3)

Compute the test statistic as follows:

$\chi^{2}=\frac{(n-1)\times s^{2}}{\sigma^{2}}$

$=\frac{(55-1)\times 94.7}{75}\\\\=68.184$

The test statistic value is, 68.184.

Decision:

$cal.\chi^{2}=68.184$

The null hypothesis will not be rejected at 5% level of significance.

Conclusion:

The variance of speeds does not exceeds 75 (mph)². Thus, concluding that driving conditions are not dangerous on this highway.

7 0

3 years ago

WHATS THE ANSWER ILL GIVE BRAINLIEST.

Gemiola [76]

A I’m pretty sure!!!

8 0

3 years ago

Which one of these answers is the actual one

Arturiano [62]

The answer is: 3 3/8 sq ft so C

3 0

3 years ago

Read 2 more answers

a carpenter has been asked to build an open box with a sqaure base. the sides of the box will cost $3 per m^2 and the base will

slamgirl [31]

<h2>Dimension of box is 2 m x 2 m x 1.33 m</h2>

Step-by-step explanation:

Let a be base side and h be the height.

Volume of box, V = a²h

The sides of the box will cost $3 per m² and the base will cost $4 per m². Cost for making is $48.

That is

4a² + 3 x 4 x a x h = 48

4a² + 12 a x h = 48

a² + 3 ah = 12

$h=\frac{12-a^2}{3a}$

So volume is

$V=a^2\times \frac{12-a^2}{3a}=4a-\frac{a^3}{3}$

At maximum volume we have derivative is zero,

$dV=4da-3\times \frac{a^2}{3}da\\\\0=4-a^2\\\\a=\pm 2$

Negative side is not possible, hence side of square base is 2m.

Substituting in a² + 3 ah = 12

2² + 3 x 2 x h = 12

h = 1.33 m

Dimension of box is 2 m x 2 m x 1.33 m

5 0

3 years ago