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1 year ago

What is the point-slope form of a line with slope -5 that contains the point a (2,-1)?

1 answer:

8 0

The point-slope form the line which has the value of slope -5 and contains a point as A(2,-1) is (y+1)=-5(x-2).

<h3>What is point slope form?</h3>

The point slope form of a line is the expression of line which has a specified slope and passes through a point.

The point slope form is givne as,

(y-y₁)=m(x-x₁)

Here, m is the slope of the line, x₁ is the x coordinate of the point by which line passes and y₁ is the y coordinate of the same point.

The slope of a line is -5. This line contains the point A (2,-1). Thus, the point slope form is,

(y-y₁)=m(x-x₁)

(y-(-1))=-5(x-2)

(y+1)=-5(x-2)

Thus, the point-slope form the line which has the value of slope -5 and contains a point as A(2,-1) is (y+1)=-5(x-2).

Learn more about the point slope form here;

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A jogger traveled at the speed of 8 km/h for 15 minutes.How far did she run

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2 years ago

Wayne bought blueberries. He uses 3/8 of the blueberries to make blueberry bread, 1/6 of the blueberries to make pancakes, and 5

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Answer:

Wayne bought 72 blueberries.

Step-by-step explanation:

To combine the fractions, convert all of the fractions to a denominator of 24.

3/8 * 3/3 = 9/24

1/6 * 4/4 = 4/24

5/12 * 2/2 = 10/24

Now add together the fractions

9/24 + 4/24 + 10/24 = 23/24

He used 23/24 of his blueberries, or 69 of them.

To find the total amount of blueberries, divide 69 by 23, then multiply that number b 24.

69 / 23 = 3

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3 years ago

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A new sample of 225 employed adults is chosen. Find the probability that less than 7.1% of the individuals in this sample hold m

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Answer:

The probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.

Step-by-step explanation:

Let X = number of individuals in the United States who held multiple jobs.

The probability that an individual holds multiple jobs is, p = 0.13.

The sample of employed individuals selected is of size, n = 225.

An individual holding multiple jobs is independent of the others.

The random variable X follows a Binomial distribution with parameters n = 225 and p = 0.13.

But since the sample size is too large Normal approximation to Binomial can be used to define the distribution of proportion p.

Conditions of Normal approximation to Binomial are:

np ≥ 10
n (1 - p) ≥ 10

Check the conditions as follows:

$np=225\times 0.13=29.25>10\\n(1-p)=225\times (1-0.13)=195.75>10$

The distribution of the proportion of individuals who hold multiple jobs is,

$p\sim N(p, \frac{p(1-p)}{n})$

Compute the probability that less than 7.1% of the individuals in this sample hold multiple jobs as follows:

$P(p$

*Use a z-table.

Thus, the probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.

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2 years ago