Given :
A submarine started at the surface of the water and was moving at -15 meters per minute.
The submarine traveled at this rate for 48 minutes before coming to rest on the ocean floor.
To Find :
The change in the submarine position.
Solution :
We need to find the position of submarine position from the surface of water.
Distance travelled = Speed × Time
Distance travelled = -15 m/min × 48 min
Distance travelled = 720 m
Therefore, the position of submarine is 720 m below the surface of ocean.
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Answer:
Step-by-step explanation:
We are given the two functions:
And we want to find:
This is equivalent to:
Then by substitution:
Evaluate:
Therefore:
Answer: B
Step-by-step explanation:
For the left side of the graph, the dot is not shaded so it is not equal, thus a and d are wrong.
c is wrong as well as the left side of the graph is x less than 1 and not more than so from the process of elimination, we get that the answer is B
Answer:
v_top = 2400 mi/hr
v_w = 400 mi/h
Step-by-step explanation:
Given:
- Total distance D = 4800 mi
- Headwind journey time taken t_up= 3 hr
- Tailwind journey time taken t_down = 2 hr
Find:
Find the top speed of Luke's snow speeder and the speed of the wind.
Solution:
- The speed of Luke v_l is in stationary frame is given by:
v_l = v_w + v_l/w
Where,
v_w: Wind speed
v_l/w: Luke speed relative to wind.
- The top speed is attained on his returned journey with tail wind. We will use distance time relationship to calculate as follows:
v_top = D / t_down
v_top = 4800 / 2
v_top = v_down = 2400 mi/hr
- Similarly his speed on his journey up with head wind was v_up:
v_up = D / t_up
v_up = 4800 / 3
v_up = 1600 mi/hr
- Now use the frame relations to find the wind speed v_w:
v_down = v_w + v_l/w
v_up = -v_w + v_l/w
- Solve equations simultaneously:
2400 = v_w + v_l/w
1600 = -v_w + v_l/w
4000 = 2*v_l/w
v_l/w = 2000 mi/h
v_w = 400 mi/h