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Oliga [24]
3 years ago
10

Solucion de ecuaciones lineales con dos variables

Mathematics
1 answer:
Reptile [31]3 years ago
8 0
Si a, b y r son números reales (y si a y b no son iguales a 0), ax+by = r se denomina ecuación lineal en dos variables. (Las “dos variables” son la x y la y.) Los números a y b se denominan los coeficientes de la ecuación ax+by = r. El número r se denomina constante del eje de ecuación + por = r.
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Answer:

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Step-by-step explanation:

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The first derivative of x^2+2y^2=16 is -x/(2y), the second is -(2y^2+x^2)/(4y^3). Find the third implicit derivative of x^2+2y^2
gtnhenbr [62]

Answer:

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Step-by-step explanation:

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Take the derivative (use quotient rule and chain rule):

d³y/dx³ = [ (4y³) (-4y dy/dx − 2x) − (-2y² − x²) (12y² dy/dx) ] / (4y³)²

d³y/dx³ = [ (-16y⁴ dy/dx − 8xy³ − (-24y⁴ dy/dx − 12x²y² dy/dx) ] / (16y⁶)

d³y/dx³ = (-16y⁴ dy/dx − 8xy³ + 24y⁴ dy/dx + 12x²y² dy/dx) / (16y⁶)

d³y/dx³ = ((8y⁴ + 12x²y²) dy/dx − 8xy³) / (16y⁶)

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Substitute:

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d³y/dx³ = ((2y² + 3x²) (-x) − 4xy²) / (8y⁵)

d³y/dx³ = (-2xy² − 3x³ − 4xy²) / (8y⁵)

8 0
3 years ago
Read 2 more answers
Please help me with this and thank you
Anarel [89]

I think it’s D sorry if you get this wrong I also have to do my work

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