(-4n^(2))* (5n^(7)):-20n to the power of 9
(2x)^(3)*(5x^(4 ))^(2): 200x to the power of 11
Answer:
LETTER A
Step-by-step explanation:
I think it's correct
Answer:
B) 13/8
Step-by-step explanation:
First we need to understand what a terminating decimal is: It is a decimal that has a finite number of decimal values that are not zero, meaning that its decimal values end at some point
Let's go through our possible answers with trial and error:
A) 8/9
8/9 = 0.888888888888...9 (Incorrect)
B) 13/8
13/8 = 1.625 (Correct)
C) 4/3
4/3 = 1.3333333333...4 (Incorrect)
D) 6/11
6/11 = 0.545454545454...54 (Incorrect
13/8 is our answer because in decimal form it is a terminating decimal.
Given the equation:
We will use the following rule to find the solution to the equation:
![x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
From the given equation: a = 6, b = 7, c = 2
So,
![\begin{gathered} x=\frac{-7\pm\sqrt[]{7^2-4\cdot6\cdot2}}{2\cdot6}=\frac{-7\pm\sqrt[]{1}}{12}=\frac{-7\pm1}{12} \\ x=\frac{-7-1}{12}=-\frac{8}{12}=-\frac{2}{3} \\ or,x=\frac{-7+1}{12}=-\frac{6}{12}=-\frac{1}{2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%3D%5Cfrac%7B-7%5Cpm%5Csqrt%5B%5D%7B7%5E2-4%5Ccdot6%5Ccdot2%7D%7D%7B2%5Ccdot6%7D%3D%5Cfrac%7B-7%5Cpm%5Csqrt%5B%5D%7B1%7D%7D%7B12%7D%3D%5Cfrac%7B-7%5Cpm1%7D%7B12%7D%20%5C%5C%20x%3D%5Cfrac%7B-7-1%7D%7B12%7D%3D-%5Cfrac%7B8%7D%7B12%7D%3D-%5Cfrac%7B2%7D%7B3%7D%20%5C%5C%20or%2Cx%3D%5Cfrac%7B-7%2B1%7D%7B12%7D%3D-%5Cfrac%7B6%7D%7B12%7D%3D-%5Cfrac%7B1%7D%7B2%7D%20%5Cend%7Bgathered%7D)
So, the answer will be option B) x = -1/2, -2/3
Answer:
4 gigabytes
Step-by-step explanation:
Equation: 68.50=48+5x
