Answer:
0.95
(Don't have paper, because I accidentally threw away paper )
Answer:
x= - 41/6, y= -6/23
Step-by-step explanation:
2x - 3y= - 1 ...(1)
0.8x - 3.5y=1/5 ...(2)
(2)×10 : 8x - 35y= 2 ... (3)
(1)×4 : 4x-12y= - 4 ...(4)
(3)-(4): 8x-35y=2
8x-12y= -4
_________
- 23y= 6
y= - 6/23
Substitute y= - 6/23 into any equation
Exp : 2x - 3(-6/23) = - 1
2x+18/23 = - 1
2x = - 41/3
x= - 41/6
Answer:
P(A∩B) = 0.522
Step-by-step explanation:
Let's call A the event that a puppy is adopted and B the probability that a puppy live 7 or more years
So, the probability P(A∩B) that a randomly selected puppy in the shelter will get adopted and live 7 or more years is:
P(A∩B) = P(A)*P(B/A)
Because A and B are not independents.
Then, the probability P(A) that a puppy is adopted is 58% and the probability P(B/A) that a puppy live 7 or more years given that the puppy is adopted is 90%.
Finally, replacing the values, we get:
P(A∩B) = 0.58*0.9 = 0.522
It means that the 52.2% of the puppies are adopted and live 7 or more years.
It is 2 5/12
<span><span>
=<span><span>(25×4)−(7×6)/</span><span>6×4</span></span></span></span><span><span>=<span><span>100−42/</span>24</span></span></span><span><span>=<span>58/24</span></span></span>Simplifying 58/24, the answer is<span><span>=2 <span>5/12</span></span></span>