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tatyana61 [14]
4 years ago
9

Which type of environmental scientist is likely to study how different species of birds interact? a. Hydrologist b. Toxicologist

c. Oceanographer d. Ecologist Please select the best answer from the choices provided A B C D
Physics
2 answers:
aleksandr82 [10.1K]4 years ago
6 0
The correct answer is D. ecologist
mixer [17]4 years ago
4 0

Answer: d. Ecologists

Ecologist are scientists who studies the relationship between living things and their surrounding environment, also the relationship between distinct species, interaction among the members of the same species. They surveys the biodiversities, to know such relationships.

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The orbital period of a satellite is 2 × 106 s and its total radius is 2.5 × 1012 m. The tangential speed of the satellite, writ
LenaWriter [7]

The orbital period of the satellite[T] is given as 2*10^{6} S.

The radius of the satellite is given [R] 2.5*10^{12} m.

we are asked here to calculate the tangential speed of the satellite.

Before going to get the solution first we have understand the tangential speed.

The tangential speed of a satellite is given as the speed required to keep the satellite along the orbit. If satellite speed is less than tangential speed,there is the chance of it falling down towards earth. If it is more,then it will deviate from it orbit and can't stick to the orbit further.In a simple way  the tangential speed is the linear speed of an object in a circular path.

Now we have to calculate the tangential speed [V].

Mathematically the tangential speed [V]   written as -

                                V=\frac{2\pi R}{T}

where T is the time period of the satellite and R is the radius of the satellite.

                        V=\frac{2*3.14*10^{12} }{2*10^{6} }

                               = 7.85*10^{6} m/s

There is also another way through which we can get  the solution as explained below-

We know that the tangential speed of a satellite V=\sqrt{\frac{GM}{R^{2} } }

where G is the gravitational constant and M is the mas of central object.

But we know that g=\frac{GM}{R^{2} }

                               ⇒GM=gR^{2}  where g is the acceleration due to gravity of that central object.


Hence    V=\sqrt{\frac{gR^{2} }{R} }

               ⇒   V=\sqrt{gR}

By knowing the value of g due to that central object we can also calculate its tangential speed.

                           

 




7 0
3 years ago
Read 2 more answers
A topic list is a list of important content and material which will be covered on a test.   Please select the best answer from t
Iteru [2.4K]
Sounds T to me. My teacher used to give those out.
6 0
3 years ago
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Which of Newton's laws is described below?
Marrrta [24]

Answer:

B second law

Explanation:

4 0
2 years ago
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Complete the following table. Be sure to include units in your answer.
mel-nik [20]

Answer:

Complete the following table. Be sure to include units in your answer.

Explanation:

all you have to do is mautiply them

6 0
3 years ago
A 0.537-kg basketball is dropped out of a window that is 5.88 m above the ground. The ball is caught by a person whose hands are
Monica [59]

Answer:

a) 20.54 J

b) 30.97 J

c) 10.43 J

d) -20.54 J

Explanation:

m = Mass

g = Acceleration due to gravity = 9.81 m/s²

h = Height

W=mgh\\\Rightarrow W=0.537\times 9.81\times (5.88-1.98)\\\Rightarrow W=0.537\times 9.81\times 3.9\\\Rightarrow W=20.54\ J

Work done by the ball's weight is 20.54 J

W=mgh\\\Rightarrow W=0.537\times 9.81\times (5.88)\\\Rightarrow W=30.97\ J

Gravitational potential energy of the basketball, relative to the ground, when it is released is 30.97 J

W=mgh\\\Rightarrow W=0.537\times 9.81\times (1.98)\\\Rightarrow W=10.43\ J

Gravitational potential energy of the basketball, relative to the ground, when it is released is 10.43 J

Change in gravitational potential energy

\Delta U=10.43-30.97=-20.54\ J

Change in gravitational potential energy is given by -20.54 J

4 0
4 years ago
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