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Nataly [62]
3 years ago
5

Explain the difference between weight and mass in terms of vectors and scalars

Physics
2 answers:
Jet001 [13]3 years ago
7 0

Answer:

hatdog.

Explanation:

havahwbscwuanw wjak

Aneli [31]3 years ago
7 0

espero que te sirva

amigo

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If a car can go from 0 to 60 km/h in 8.0 seconds, what would be its final speed after 5.0 seconds if its starting speed were 50
dmitriy555 [2]

Answer:

This question assumes that the car accelerates at the same rate as when it went from 0 to 60km/h

24.29m/s or 87.4km/h

Explanation:

Let's find the acceleration of the car:

let vi=0, vf=60km/h (16.67m/s), Δt = 8.0s

a = (vf-vi)/Δt

a = (16.67m/s-0)/8.0

a = 2.08m/s^2

Now we can use this acceleration to find vf in the second part:

50km/h is 13.89m/s

a = (vf-vi)Δt

vf = aΔt + vi

vf = 2.08m/s^2*5.0+13.89m/s

vf = 24.29m/s (87.4km/h)

3 0
2 years ago
Please help me with this question​
Ksju [112]

Answer:

i can not read that sorry

4 0
3 years ago
what equastion do you use to solve Riders in a carnival ride stand with their backs against the wall of a circular room of diame
Hitman42 [59]

Answer:

μsmín = 0.1

Explanation:

  • There are three external forces acting on the riders, two in the vertical direction that oppose each other, the force due to gravity (which we call weight) and the friction force.
  • This friction force has a maximum value, that can be written as follows:

       F_{frmax} = \mu_{s} *F_{n} (1)

       where  μs is the coefficient of static friction, and Fn is the normal force,

       perpendicular to the wall and aiming to the center of rotation.

  • This force is the only force acting in the horizontal direction, but, at the same time, is the force that keeps the riders rotating, which is the centripetal force.
  • This force has the following general expression:

       F_{c} =  m* \omega^{2} * r (2)

       where ω is the angular velocity of the riders, and r the distance to the

      center of rotation (the  radius of the circle), and m the mass of the

      riders.

      Since Fc is actually Fn, we can replace the right side of (2) in (1), as

      follows:

     F_{frmax} = m* \mu_{s} * \omega^{2} * r (3)

  • When the riders are on the verge of sliding down, this force must be equal to the weight Fg, so we can write the following equation:

       m* g = m* \mu_{smin} * \omega^{2} * r (4)

  • (The coefficient of static friction is the minimum possible, due to any value less than it would cause the riders to slide down)
  • Cancelling the masses on both sides of (4), we get:

       g = \mu_{smin} * \omega^{2} * r (5)

  • Prior to solve (5) we need to convert ω from rev/min to rad/sec, as follows:

      60 rev/min * \frac{2*\pi rad}{1 rev} *\frac{1min}{60 sec} =6.28 rad/sec (6)

  • Replacing by the givens in (5), we can solve for μsmín, as follows:

       \mu_{smin} = \frac{g}{\omega^{2} *r}  = \frac{9.8m/s2}{(6.28rad/sec)^{2} *2.5 m} =0.1 (7)

5 0
3 years ago
A spring balance attempts to drag an object across a table, but the object does not move because of the force of friction acting
Luda [366]
Moving
.................................................
4 0
3 years ago
True or False. The Magnitude of the induced voltage in a coil of wire depends on how quickly the magnetic flux through the coil
EleoNora [17]

Answer:

Yes, its true

Explanation:

hdheheishdhieijzuwhs

5 0
3 years ago
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