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Montano1993 [528]
3 years ago
13

What name is given to the force on an object caused by the earth's gravitational pull?

Physics
1 answer:
FrozenT [24]3 years ago
6 0
Acceleration due to gravity
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Mike is a runner. Mike runs 200m in 25s; what is his average velocity during the run? assume that units are in m/s. (asap, will
maw [93]
Velocity is displacement/time
(Displacement is the overall change in distance)

So you’ll want to divide 200 by 25, which should give you:

8 m/s

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Linear expansivity?<br>​
shusha [124]

Linear expansivity, area expansivity and volume or cubic expansivity are

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When exposed to a radioactive source which emits 1.2-MeV gamma-rays, a particular material is found to have a half-value thickne
iren2701 [21]

Answer:E

Explanation:

It is given that Energy of gamma ray is E=1.2 Mev

Shielding effect can be measured by measuring the fraction of gamma rays blocked by shield. If certain thickness will able to block half the radiation then to block 75% radiation we need to add same amount of thickness in order to block the remaining radiation.

i.e. \frac{E}{2} fraction is blocked by 10 cm thickness

then remaining radiation is \frac{E}{2}

another 10 cm thickness will block the remaining half radiation i.e. \frac{1}{2}\times \frac{E}{2}=\frac{E}{4}

so total 75 % radiation will be blocked

4 0
3 years ago
Which is the most abundant element in the Sun?
Delvig [45]
The answer is hydrogen.
5 0
3 years ago
A metal sphere with a mass of 0.026 kg rolls along a friction-less surface at 3.7 m/s and strikes a stationary sphefe having a m
zubka84 [21]

The force applied to the second ball by the first ball is 6.734 × 10^-4 N.

<h3>What is impulse of force?</h3>

The impulse of force is defined as the sum of the average force and the duration it is applied.

If the mass of the item remains constant, the impulse of force equals the change in momentum of the object.

Given that:  mass of a metal sphere: m = 0.026 kg.

Initial speed of the sphere: u = 3.7 m/s.

When the sphere stops completely, its change in momentum = mu - 0

= 0.026×3.7 N-s.

= 0.0962 N-s.

As the spheres are in contact for 0.007s before the second sphere is shot off down the track, the force applied  to the second ball =

change in momentum of 1st ball × time of contact

= 0.0962 × 0.007 N

= 0.0006734 N

= 6.734 × 10^-4 N.

Hence,  the force applied  to the second ball is  6.734 × 10^-4 N.

Learn more about impulse force here:

brainly.com/question/29787329

#SPJ1

7 0
1 year ago
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