The students at a High School earned money for an international animal rescue foundation. 82 seniors earned an average $26.75 pe
2 answers:
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Answer:
10 times greater is the value of 5 in 3,590 than the value of 5 in 359.
Step-by-step explanation:
To find : How many times greater is the value of 5 in 3,590 than the value of 5 in 359 ?
Solution :
The place value stem is
Thousand Hundred Tens Ones
1000 100 10 1
The value of 5 in 3,590 is at hundred place
So,
The value of 5 in 359 is at tens place
So,
Number of time greater is the value of 5 in 3,590 than the value of 5 in 359 is given by,
Therefore, 10 times greater is the value of 5 in 3,590 than the value of 5 in 359.
Answer:
If we compare the p value and the significance level given we see that
so we can conclude that we have enough evidence to reject the null hypothesis, and the true mean is lower than 8 ppb at 1% of signficance. We need to be careful with this interpretation since the p value is near to the significance level.
Step-by-step explanation:
Data given and notation
represent the mean height for the sample
sample size
represent the value that we want to test
represent the significance level for the hypothesis test.
t would represent the statistic (variable of interest)
represent the p value for the test (variable of interest)
State the null and alternative hypotheses.
We need to conduct a hypothesis in order to check if the true mean is less than 8, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:
(1)
t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".
Calculate the statistic
We can replace in formula (1) the info given like this:
P-value
The first step is calculate the degrees of freedom, on this case:
Since is a one side test the p value would be:
Conclusion
If we compare the p value and the significance level given we see that
so we can conclude that we have enough evidence to reject the null hypothesis, and the true mean is lower than 8 ppb at 1% of signficance. We need to be careful with this interpretation since the p value is near to the significance level.