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3 years ago

What is (5+2)[6-(3+2)]=

Mathematics

2 answers:

Scorpion4ik [409]3 years ago

5 0

The answer is 7!!!!!!!!!! Hope this helps

zzz [600]3 years ago

4 0

Answer:

Step-by-step explanation:

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What is an equivalent ratio to 5/6

Evgen [1.6K]

Just times everything by something
examples
10/12
20/24

8 0

3 years ago

6/1 x 7/4 in simplest form

dalvyx [7]

The answer would be 10.5 in decimal form. In fraction form you could reduce 6 and 4 and make the six a 3 and make the four a 2. Then multiply it out. Which would be 3/1 multiplied by 7/2 = 21/2

6 0

3 years ago

Circle the integer(s) that have an absolute value of 11

erik [133]

Answer: shouldn't it be -11?

Step-by-step explanation:

im p sure to find the AV its just like the positive version of a number. Kinda rusty since i did this a long time ago lol

3 0

3 years ago

At what point does the curve have maximum curvature? Y = 4ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as

MAXImum [283]

<u>Answer-</u>

At $x= \frac{1}{2304e^4-16e^2}$ the curve has maximum curvature.

<u>Solution-</u>

The formula for curvature =

$K(x)=\frac{{y}''}{(1+({y}')^2)^{\frac{3}{2}}}$

Here,

$y=4e^{x}$

Then,

${y}' = 4e^{x} \ and \ {y}''=4e^{x}$

Putting the values,

$K(x)=\frac{{4e^{x}}}{(1+(4e^{x})^2)^{\frac{3}{2}}} = \frac{{4e^{x}}}{(1+16e^{2x})^{\frac{3}{2}}}$

Now, in order to get the max curvature value, we have to calculate the first derivative of this function and then to get where its value is max, we have to equate it to 0.

${k}'(x) = \frac{(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})}{(1+16e^{2x} )^{2}}$

Now, equating this to 0

$(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x}) =0$

$\Rightarrow (1+16e^{2x})^{\frac{3}{2}}-(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})$

$\Rightarrow (1+16e^{2x})^{\frac{3}{2}}=(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})$

$\Rightarrow (1+16e^{2x})^{\frac{1}{2}}=48e^{2x}$

$\Rightarrow (1+16e^{2x})}=48^2e^{2x}=2304e^{2x}$

$\Rightarrow 2304e^{2x}-16e^{2x}-1=0$

Solving this eq,

we get $x= \frac{1}{2304e^4-16e^2}$

∴ At $x= \frac{1}{2304e^4-16e^2}$ the curvature is maximum.

6 0

3 years ago

HELP I DONT GET IT!!!For the system below solve using linear combinations method 2a+3b=1 and -2a+b=11

Maksim231197 [3]

Linear combination method just means to add the equations so that one variable with cancel. In this case the a values are already set up so that they will cancel.
2a + 3b = 1
-2a + b = 11
4b = 12
b = 3

now put 3 back into either of the original equations and solve for a.
2a + 3(3) = 1
2a + 9 = 1
2a = -8
a = -4
(-4,3)

3 0

3 years ago

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