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expeople1 [14]
3 years ago
8

An isosceles triangle has a base of 12 cm and legs measuring 18 cm. How wide is the base of a similar triangle with legs measuri

ng 22 cm?
Mathematics
1 answer:
Mama L [17]3 years ago
6 0
So in similar triangles the angles are the same, only the side lengths change so you have to use ratios to find this:
18:22
This is the ratio but it needs to be simplified.
Divide each side by 18 so that the right side is one:
1:1 2/9
now we use this ratio with 12cm where 12 is on the right. You multiply both sides by 12 and it becomes:
12:14 24/9
or
12:16 6/9
or 
12:16 2/3
Therefore the base of the second triangle is 16 2/3 cm

Hope this helps :)
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Kobotan [32]
<h3><u>The value of x is greater than or equal to -4.</u></h3>

(3x + 17) ≥ 5

Subtract 17 from both sides.

3x ≥ -12

Divide both sides by 3.

x  ≥ -4


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2 years ago
Is 5.2 greater than 60.3
yanalaym [24]
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4 0
3 years ago
Read 2 more answers
A public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes. Kar
ch4aika [34]

Answer:

We conclude that the mean waiting time is less than 10 minutes.

Step-by-step explanation:

We are given that a public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes.

Karen took bus number 14 during peak hours on 18 different occasions. Her mean waiting time was 7.8 minutes with a standard deviation of 2.5 minutes.

Let \mu = <u><em>mean waiting time for bus number 14.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 10 minutes      {means that the mean waiting time is more than or equal to 10 minutes}

Alternate Hypothesis, H_A : \mu < 10 minutes    {means that the mean waiting time is less than 10 minutes}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                       T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean waiting time = 7.8 minutes

             s = sample standard deviation = 2.5 minutes

             n = sample of different occasions = 18

So, <u><em>test statistics</em></u> =  \frac{7.8-10}{\frac{2.5}{\sqrt{18} } }  ~ t_1_7

                              =  -3.734

The value of t test statistics is -3.734.

Now, at 0.01 significance level the t table gives critical value of -2.567 for left-tailed test.

Since our test statistic is less than the critical value of t as -3.734 < -2.567, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean waiting time is less than 10 minutes.

5 0
3 years ago
What is the lest common denominator of 1/12 and 5/8
Sonja [21]
The LCM is 24.
1/12=2/24
5/8=15/24
6 0
3 years ago
John invested his inheritance of $12000 in 3 different funds part in a money market fund paying 3% interest annually Parton monu
Leokris [45]

Answer:

John invested $2,000 in money-market fund, $3,000 in municipal bonds, and $7,000 in mutual funds.

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

John invested his inheritance of $12,000 in three different funds: part in a money-market fund paying 3% interest annually; part in municipal bonds paying 4% annually; and the rest in mutual funds paying 7% annually. John invested $4,000 more in mutual funds than he invested in municipal bonds. The total interest earned in one year was $670. How much did he invest in each type of fund?

The explanation of the answer is now given as follows:

Let a, b and c represent the amount invested in money-market fund, municipal bonds and mutual funds respectively. Therefore, the sum of the three principal amounts can be represented as follows:

a + b + c = 12,000 ……………………….. (1)

Since John invested $4,000 more in mutual funds than he invested in municipal bonds, we have:

c = b + 4,000 ……………………………. (2)

The total amount of interest earned from each fund can be represented as follows:

0.03a + 0.04b + 0.07c = 670 ………………. (3)

Substituting equation (2) into equation (1), we have:

a + b + b + 4,000 = 12,000

a + 2b = 12,000 – 4,000

a + 2b = 8,000

a = 8,000 – 2b ……………………….. (4)

Also, substituting equation (2) into equation (3), we have:

0.03a + 0.04b + 0.07(b + 4,000) = 670

0.03a + 0.04b + 0.07b + 280 = 670

0.03a + 0.04b + 0.07b 0 = 670 – 280

0.03a + 0.11b = 390 ,,,,,,,,,,,,,,,,,,,,,, (5)

Substituting equation (4) into equation (5) and solve for b, we have:

0.03(8,000 – 2b) + 0.11b = 390

240 – 0.06b + 0.11b = 390

240 + 0.05b = 390

0.05b = 390 – 240

0.05b = 150

b = 150 / 0.05

b = 3,000

Substituting b = 3,000 into equation (2), we have:

c = 3,000 + 4,000

c = 7,000

Also, substituting b = 3,000 into equation (4), we have:

a = 8,000 – (2 * 3,000)

a = 8,000 – 6,000

a = 2,000

Therefore, John invested $2,000 in money-market fund, $3,000 in municipal bonds, and $7,000 in mutual funds.

8 0
3 years ago
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