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Serjik [45]
1 year ago
7

How do you find the derivative of 1/logx?

Mathematics
1 answer:
valentina_108 [34]1 year ago
5 0

The derivative of 1/logx is With the chain rule.

1log(x)=log(x)−1 is ,= -1xlog(x)2 .

The by-product of logₐ x (log x with base a) is 1/(x ln a). Here, the thrilling issue is that we have "ln" withinside the by-product of "log x". Note that "ln" is referred to as the logarithm (or) it's miles a logarithm with base "e".

The by-product of 1/log x is -1/x(log x)^2. Note that 1/logx is the reciprocal of log.

With the chain rule. \\ 1log(x)=log(x)−1  \\ So you follow the chain rule to the electricity after which to the log: \\ ddxlog(x)−1=−1⋅log(x) \\  \\−2⋅ddxlog(x)  \\ =−1log(x)21x  \\ =−1xlog(x)2 .

Read more about derivatives;

brainly.com/question/23819325

#SPJ4

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Answer:

\red{ \bold{ V = \sqrt{\frac{2(E - mgh)}{M}}}}

Step-by-step explanation:

E = MV^2 ÷ 2 + mgh \\  \\ E - mgh = MV^2 ÷ 2  \\  \\  2(E - mgh)= MV^2   \\  \\  \frac{2(E - mgh)}{M}=V^2  \\  \\  \sqrt{\frac{2(E - mgh)}{M}}  = V \\  \\ \red{ \bold{ V = \sqrt{\frac{2(E - mgh)}{M}}}}

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3 years ago
Ashley is packing her bags for her vacation. She has 8 unique Fabergé eggs, but only 5 fit in her bag. How many different groups
irakobra [83]

Answer:

56 groups of 5 Fabergé eggs can be taken.

Step-by-step explanation:

It is given that Ashley is packing her bags for her vacation. She has 8 unique Fabergé eggs, but only 5 fit in her bag. In order to find how many different groups of 5 Faberge' eggs can she take, we apply the combination formula:

8C_{5}=\frac{8!}{5!(8-5)!}

8C_{5}=\frac{8!}{5!3!}

8C_{5}=\frac{8{\times}7{\times}6{\times}5!}{5!{\times}3{\times}2}

8C_{5}=56

Thus, 56 groups of 5 Fabergé eggs can be taken.

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Answer:

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= 4 * -11

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b. He then deposits $11 once every day for 4 days.

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c. The integer for withdrawals is a negative figure to show that the balance was decreasing. The Integer for deposits is positive to show that the balance was increasing.

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