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1 year ago

How do you find the derivative of 1/logx?

Mathematics

1 answer:

valentina_108 [34]1 year ago

5 0

The derivative of 1/logx is With the chain rule.

1log(x)=log(x)−1 is ,= -1xlog(x)2 .

The by-product of logₐ x (log x with base a) is 1/(x ln a). Here, the thrilling issue is that we have "ln" withinside the by-product of "log x". Note that "ln" is referred to as the logarithm (or) it's miles a logarithm with base "e".

The by-product of 1/log x is -1/x(log x)^2. Note that 1/logx is the reciprocal of log.

$With the chain rule. \\ 1log(x)=log(x)−1 \\ So you follow the chain rule to the electricity after which to the log: \\ ddxlog(x)−1=−1⋅log(x) \\ \\−2⋅ddxlog(x) \\ =−1log(x)21x \\ =−1xlog(x)2 .$

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Answer:

$\red{ \bold{ V = \sqrt{\frac{2(E - mgh)}{M}}}}$

Step-by-step explanation:

$E = MV^2 ÷ 2 + mgh \\ \\ E - mgh = MV^2 ÷ 2 \\ \\ 2(E - mgh)= MV^2 \\ \\ \frac{2(E - mgh)}{M}=V^2 \\ \\ \sqrt{\frac{2(E - mgh)}{M}} = V \\ \\ \red{ \bold{ V = \sqrt{\frac{2(E - mgh)}{M}}}}$

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3 years ago

Ashley is packing her bags for her vacation. She has 8 unique Fabergé eggs, but only 5 fit in her bag. How many different groups

irakobra [83]

Answer:

56 groups of 5 Fabergé eggs can be taken.

Step-by-step explanation:

It is given that Ashley is packing her bags for her vacation. She has 8 unique Fabergé eggs, but only 5 fit in her bag. In order to find how many different groups of 5 Faberge' eggs can she take, we apply the combination formula:

$8C_{5}=\frac{8!}{5!(8-5)!}$

$8C_{5}=\frac{8!}{5!3!}$

$8C_{5}=\frac{8{\times}7{\times}6{\times}5!}{5!{\times}3{\times}2}$

$8C_{5}=56$

Thus, 56 groups of 5 Fabergé eggs can be taken.

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3 years ago

withdraws $ from bank account once each day for days. What integer represents the change in the amount in the account? Use pen

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Answer:

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He does this 4 times so;

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c. The integer for withdrawals is a negative figure to show that the balance was decreasing. The Integer for deposits is positive to show that the balance was increasing.

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