All categories

6 months ago

How do you find the derivative of 1/logx?

Mathematics

1 answer:

valentina_108 [34]6 months ago

5 0

The derivative of 1/logx is With the chain rule.

1log(x)=log(x)−1 is ,= -1xlog(x)2 .

The by-product of logₐ x (log x with base a) is 1/(x ln a). Here, the thrilling issue is that we have "ln" withinside the by-product of "log x". Note that "ln" is referred to as the logarithm (or) it's miles a logarithm with base "e".

The by-product of 1/log x is -1/x(log x)^2. Note that 1/logx is the reciprocal of log.

$With the chain rule. \\ 1log(x)=log(x)−1 \\ So you follow the chain rule to the electricity after which to the log: \\ ddxlog(x)−1=−1⋅log(x) \\ \\−2⋅ddxlog(x) \\ =−1log(x)21x \\ =−1xlog(x)2 .$

You might be interested in

Translate this sentence into a equation. 117 is the product of Delia's age and 9.

Tju [1.3M]

Let Delta's age be d

$d=\frac{117}{9}$

8 0

2 years ago

A healthcare provider monitors the number of CAT scans performed each month in each of its clinics. The most recent year of data

Rasek [7]

Answer: a. 1.981 < μ < 2.18

b. Yes.

Step-by-step explanation:

A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.

First, we calculate mean of the sample:

$\overline{x}=\frac{\Sigma x}{n}$

$\overline{x}=\frac{2.31=2.09+...+1.97+2.02}{12}$

$\overline{x}=$ 2.08

Now, we estimate standard deviation:

$s=\sqrt{\frac{\Sigma (x-\overline{x})^{2}}{n-1} }$

$s=\sqrt{\frac{(2.31-2.08)^{2}+...+(2.02-2.08)^{2}}{11} }$

s = 0.1564

For t-score, we need to determine degree of freedom and $\frac{\alpha}{2}$ :

df = 12 - 1

df = 11

$\alpha$ = 1 - 0.95

α = 0.05

$\frac{\alpha}{2}=$ 0.025

Then, t-score is

$t_{11,0.025}$ = 2.201

The interval will be

$\overline{x}$ ± $t.\frac{s}{\sqrt{n} }$

2.08 ± $2.201\frac{0.1564}{\sqrt{12} }$

2.08 ± 0.099

The 95% two-sided CI on the mean is 1.981 < μ < 2.18.

B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.

8 0

2 years ago

Explain what |-13| means and how to simplify.

poizon [28]

The two bars ( | | ) symbolize absolute value

Absolute value is essentially just making the number given positive.

If the given number is already positive then the absolute value is the same as the original number

|-13| is 13

The absolute value of -13 is 13

Hope this helped!

~Just a girl in love with Shawn Mendes

4 0

3 years ago

Read 2 more answers

30 points for RIGHT ANSWER

juin [17]

The answer is 18 I’m pretty certain so D

8 0

2 years ago

12.4. Measure of Dispersion 2076 Q.No. 15 Find the standard deviation of: 4, 6, 8, 10, 12.

Alenkinab [10]

Answer:

Standard deviation of given data = 3.16227

Step-by-step explanation:

Step(i):-

Given sample size 'n' = 5

Given data 4, 6,8,10,12

$Mean = \frac{4+6+8+10+12}{5} = 8$

Mean of the sample x⁻ = 8

Standard deviation of the sample

$S.D = \sqrt{\frac{Sum(x-x^{-} )^{2} }{n-1}}$

Step(ii):-

Given data

x : 4 6 8 10 12

x-x⁻ : 4 - 8 6-8 8-8 10-8 12-8

(x-x⁻) : -4 -2 0 2 4

(x-x⁻)² : 16 4 0 4 16

$S.D = \sqrt{\frac{Sum(x-x^{-} )^{2} }{n-1}}$

$S.D = \sqrt{\frac{16+4+0+4+16}{4}}$

S.D = √10 = 3.16227

Final answer:-

The standard deviation = 3.16227

8 0

2 years ago