Find the z-scores for the two scores in the given interval.
![z=\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
For the score x =391,
![z=\frac{391-486}{95}=\frac{-95}{95}=-1](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B391-486%7D%7B95%7D%3D%5Cfrac%7B-95%7D%7B95%7D%3D-1)
.
For the score x = 486,
![z=\frac{486-486}{95}=0](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B486-486%7D%7B95%7D%3D0)
Now you want the area (proportion of data) under the normal distribution from z = -1 to z = 0. The Empirical Rule says that 68% of the data falls between z = -1 to z = 1. But the curve is symmetrical around the vertical axis at z = 0, so the answer you want is HALF of 68%.
6 x 3 is 18. y is equal to 4. 18 minus 4 is 14. The answer is 14.
<h2>
Answer:</h2>
cylinder
<h2>
Step-by-step explanation:</h2>
Archimedes was a brilliant mathematician. This man rose the formula of the volume of a sphere by comparing this shape to a cylinder. The volume of a sphere is hard to calculate by comparing this object to a cube. So Archimedes imagined cutting a sphere into two halves, called hemispheres. So an hemisphere gave him a flat surface, which is easier to work with. Therefore, if he'd find the volume of a hemisphere, then he'd multiply the result by 2 and would get the volume of a sphere. Then he imagined a hemisphere within a cylinder as the one shown below. Also, he imagined a cone within the same cylinder. <em>What did he find? </em>He found that the volume of the hemisphere should be equal to the volume of the cylinder minus the volume of the cone:
![V=\pi r^3-\frac{1}{3}\pi r^3 \\ \\ V=\frac{2}{3} \pi r^3](https://tex.z-dn.net/?f=V%3D%5Cpi%20r%5E3-%5Cfrac%7B1%7D%7B3%7D%5Cpi%20r%5E3%20%5C%5C%20%5C%5C%20V%3D%5Cfrac%7B2%7D%7B3%7D%20%5Cpi%20r%5E3)
Then the volume of a sphere is twice this volume:
![\boxed{V=\frac{4}{3} \pi r^3}](https://tex.z-dn.net/?f=%5Cboxed%7BV%3D%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%20r%5E3%7D)
Set the denominatior equal to zero to find vertical asymptotes. Horizontal take the highest degree of the top and divide it by the highest degree of the bottom.
![{x}^{2} - 9 = 0 \\ {x}^{2} = 9 \\ x = 3 \\ x = - 3 \\ \\ \frac{ {x}^{2} }{ {x}^{2} } = 1 \\ y = 1](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20-%209%20%3D%200%20%5C%5C%20%20%7Bx%7D%5E%7B2%7D%20%20%3D%209%20%5C%5C%20x%20%3D%203%20%5C%5C%20x%20%3D%20%20-%203%20%5C%5C%20%20%5C%5C%20%20%5Cfrac%7B%20%7Bx%7D%5E%7B2%7D%20%7D%7B%20%7Bx%7D%5E%7B2%7D%20%7D%20%20%3D%201%20%5C%5C%20y%20%3D%201)
Vertical: x=3, x=-3
Horizontal : y=1
Answer: 22 quarters
Step-by-step explanation:
Let N be the number of nickels.
Then the number of quarters is (55-N)
The nickels contribute 5N cents to the total.
The quarters contribute 25*(55-N) cents to the total.
5N + 25*(55-N) = 715
5N + 1375 - 25N = 715
-20N = 715 - 1375 = -660
![N=\frac{-660}{-20}](https://tex.z-dn.net/?f=N%3D%5Cfrac%7B-660%7D%7B-20%7D)
![=33](https://tex.z-dn.net/?f=%3D33)
![55-33=22](https://tex.z-dn.net/?f=55-33%3D22)
So there is 22 quarters inside the jar.
Check to see if my answer is correct-
33*5 + 22*25 = 715 cents