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Serjik [45]
9 months ago
7

How do you find the derivative of 1/logx?

Mathematics
1 answer:
valentina_108 [34]9 months ago
5 0

The derivative of 1/logx is With the chain rule.

1log(x)=log(x)−1 is ,= -1xlog(x)2 .

The by-product of logₐ x (log x with base a) is 1/(x ln a). Here, the thrilling issue is that we have "ln" withinside the by-product of "log x". Note that "ln" is referred to as the logarithm (or) it's miles a logarithm with base "e".

The by-product of 1/log x is -1/x(log x)^2. Note that 1/logx is the reciprocal of log.

With the chain rule. \\ 1log(x)=log(x)−1  \\ So you follow the chain rule to the electricity after which to the log: \\ ddxlog(x)−1=−1⋅log(x) \\  \\−2⋅ddxlog(x)  \\ =−1log(x)21x  \\ =−1xlog(x)2 .

Read more about derivatives;

brainly.com/question/23819325

#SPJ4

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The manager of a grocery store wants to determine the average amount of money spent at his store as it compares to the average d
Nezavi [6.7K]

Answer:

The average spent at his store is of $37.60.

The average spent at his competitor's store is of $48.53.

Step-by-step explanation:

Average of a data set:

The mean of a data set is the sum of all values divided by the number of values.

His store:

15 orders.

Prices of: 41, 38, 19, 30, 21, 53, 34, 34, 37, 29, 50, 43, 57, 28, 50

The average is:

M = \frac{41 + 38 + 19 + 30 + 21 + 53 + 34 + 34 + 37 + 29 + 50 + 43 + 57 + 28 + 50}{15} = 37.6

The average spent at his store is of $37.60.

Store of the competitor:

15 orders

Prices of: 86, 15, 75, 40, 51, 60, 27, 45, 112, 7, 65, 31, 18, 27, 69

The average is:

M = \frac{86 + 15 + 75 + 40 + 51 + 60 + 27 + 45 + 112 + 7 + 65 + 31 + 18 + 27 + 69}{15} = 48.53

The average spent at his competitor's store is of $48.53.

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Step-by-step explanation:

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