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Serjik [45]
1 year ago
7

How do you find the derivative of 1/logx?

Mathematics
1 answer:
valentina_108 [34]1 year ago
5 0

The derivative of 1/logx is With the chain rule.

1log(x)=log(x)−1 is ,= -1xlog(x)2 .

The by-product of logₐ x (log x with base a) is 1/(x ln a). Here, the thrilling issue is that we have "ln" withinside the by-product of "log x". Note that "ln" is referred to as the logarithm (or) it's miles a logarithm with base "e".

The by-product of 1/log x is -1/x(log x)^2. Note that 1/logx is the reciprocal of log.

With the chain rule. \\ 1log(x)=log(x)−1  \\ So you follow the chain rule to the electricity after which to the log: \\ ddxlog(x)−1=−1⋅log(x) \\  \\−2⋅ddxlog(x)  \\ =−1log(x)21x  \\ =−1xlog(x)2 .

Read more about derivatives;

brainly.com/question/23819325

#SPJ4

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anastassius [24]

Answer:

x = 3

Step-by-step explanation:

Here, we want to find the value of x

By mathematical convention;

NM = NL + LM

Now, substitute individual values

3x + 13 = (6x-5) + (2x + 3)

3x + 13 = 6x-5 + 2x + 3

3x + 13 = 8x -2

Collect like terms

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x = 15/5

x = 3

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Step-by-step explanation:

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WILL GIVE BRAINEST <br><br>Let f(x)=7x-4<br><br>what is f(6)<br><br>a.48<br>b.42<br>c.38<br>d.46
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Hope this helps!
4 0
3 years ago
0.403 divided by 100 what is the quotient
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4 0
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Alice's goal is to have $30 in her account. She starts with $24.60 from washing cars. She spends $8.25 at the movies. Then she e
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3 years ago
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