Exponents first, then multiply (PEMDAS)
5•5•5= 125
3•3•3= 27
27•125= 3375
How many drops per minute?
There are 16 drops per ML.
1000 ML = 1 L.
1L = 1000 ML
Therefore 1.08 L = 1.08 * 1000 = 1080 ML
16 drops per ML means I ML has 16 drops.
Therefore 1080 ML has: (1080 * 16) drops.
Number of drops per min:
Since the entire process took 3 hours = 3 * 60 minutes = 180 minutes.
Therefore Number of drops per minute = Number of Drops / Time in minutes
= (1080 * 16) /(180)
= 96 drops per minute.
#3). $124.16 will be in amount of deposit
#4) new balance, b = original balance + deposits - payments
=》 b =$782.14+$124.16 - ($450+$58.25)
=》 b = $398.05
Step-by-step explanation:
Solving
3x + -6y = 42
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '6y' to each side of the equation.
3x + -6y + 6y = 42 + 6y
Combine like terms: -6y + 6y = 0
3x + 0 = 42 + 6y
3x = 42 + 6y
Divide each side by '3'.
x = 14 + 2y
Simplifying
x = 14 + 2y
Answer:
The radius, r₂, of the ball that uses one-half the amount of rubber coating used to cover the 16-inch ball is approximately 4.66 inches
Step-by-step explanation:
The dimension of the ball with known radius = 16-inch
The surface area of the ball with 16-inch radius = 4×π×r² = π·D² = π×16² = 804.24772 in.²
Given that the ball uses one-half the rubber material coating used to cover the 16-inch ball, we have the surface area of the ball = 804.24772 in.²/2 = 402.12386 in.²
The radius, r₂ of the new ball is found as follows;
402.12386 in.² = 4×π×r₂²
r₂² = 402.12386 in.² /(4×π) ≈ 32
r₂ = √32 = 4·√2 ≈ 4.66 inches
The radius, r₂, of the ball that uses one-half the amount of rubber coating used to cover the 16-inch ball ≈ 4.66 inches.
