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AnnZ [28]
3 years ago
5

What value of c makes the equation true? (PLEASE HELP, and look at the picture)

Mathematics
2 answers:
Cloud [144]3 years ago
8 0

Answer:

\displaystyle c = 8

General Formulas and Concepts:

<u>Pre-Algebra</u>

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle \frac{3}{6} = \frac{4}{c}

<u>Step 2: Solve for </u><em><u>c</u></em>

  1. Simplify [Reduce]:                                                                                             \displaystyle \frac{1}{2} = \frac{4}{c}
  2. [Multiplication Property of Equality] Cross-multiply:                                      \displaystyle c = 8
KiRa [710]3 years ago
3 0

Answer:

c = 8

Step-by-step explanation:

\small \sf \frac{3}{6} = \frac{4}{c } \\

  • Variable c cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 6c, the least common multiple of 6,c.

c × 3 = 6 × 4

  • multiply 6 and 4 to get 24

3c = 24

  • divide both side by 3

\small \sf  \frac{3c }{3} = \frac{ 24} {3} \\

\small \sf  \frac{ \cancel{3}c }{ \cancel{3}} = \frac{ \cancel{24}} {\cancel{3}} \\

  • Divide 24 by 3 to get 8.

c = 8

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Find the value of y for the following system of equations 5x + 3y = 10 x = y - 6
viktelen [127]

Answer:

x = -1 , y = 5

Step-by-step explanation:

Solve the following system:

{5 x + 3 y = 10 | (equation 1)

x = y - 6 | (equation 2)

Express the system in standard form:

{5 x + 3 y = 10 | (equation 1)

x - y = -6 | (equation 2)

Subtract 1/5 × (equation 1) from equation 2:

{5 x + 3 y = 10 | (equation 1)

0 x - (8 y)/5 = -8 | (equation 2)

Multiply equation 2 by -5/8:

{5 x + 3 y = 10 | (equation 1)

0 x+y = 5 | (equation 2)

Subtract 3 × (equation 2) from equation 1:

{5 x+0 y = -5 | (equation 1)

0 x+y = 5 | (equation 2)

Divide equation 1 by 5:

{x+0 y = -1 | (equation 1)

0 x+y = 5 | (equation 2)

Collect results:

Answer: {x = -1 , y = 5

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3 years ago
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