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Snezhnost [94]
3 years ago
15

Ten years from now, Abdul will be twice as old as his son pavel ten years ago, Abdul was seven times as old as pavel how old are

Abdul and pavel now?
Mathematics
1 answer:
Rzqust [24]3 years ago
8 0

Answer:

Age of Pavel = y - 10

→ x - 7y = -60. Now, Calculating X. Hence, Present age of Abdul = 38.

Step-by-step explanation:

hope this is helpful.

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ANSWER THIS USING INVERSE OPERATIONS AND PROVIDE TH STEPS
Airida [17]

Answer:

x = 12

Step-by-step explanation:

5+x2 = 2x2+13

5+x2 = 4+13

5+x2÷2 = 17

5-5+x = 17-5

x = 12

5 0
3 years ago
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If D is midpoint of side BC of triangle ABC. P and Q are points lying respectively on side AB and AC such that DP is parallel to
LUCKY_DIMON [66]

See proof below

Step-by-step explanation:

Assume triangle ABC to have vertices at;

A(2,-1), B(2,-7) and C(6,-7)

D is midpoint of BC, thus D is at (4,-7)

The P and Q, are lying on side AB and AC, hence assume P is at (2,-4) and Q is at (4,-4) such at DP is parallel to QA

Plot the points on a graph tool and join the points to view the sketch.

To prove area of triangle CPQ is 1/4 area of ABC will be;

Find area ABC and CPQ then compare the areas.

Apply the distance formula to find the length of sides of the triangles then find the areas.

The distance formula is;

d=\sqrt{x_2-x_1)^2+(y_2-y_1)^2}

Length of side AB from the sketch is;

AB=\sqrt{(2-2)^2+(-7--1)^2} =\sqrt{-6^2} =\sqrt{36} =6units

Length of side BC will be;

BC=\sqrt{(-7--7)^2+(6-2)^2} =\sqrt{4^2} =\sqrt{16} =4units

Thus area of triangle ABC will be;

1/2 *base length*height ------because it is a right-triangle

1/2*4*6=12 square units

Find the lengths of all sides of triangle CPQ

Length of side PQ is half that of side BC thus PQ=2 units

Length of side PC is;

PC=\sqrt{(6-2)^2+(-7--4)^2} =\sqrt{4^2+-3^2} =\sqrt{16+9} =\sqrt{25} =5units

Length of side QC will be;

QC=\sqrt{(6-4)^2+(-7--4)^2} =\sqrt{2^2+-3^3} =\sqrt{4+9} =\sqrt{13}

QC= √13 = 3.6 units

Find area of triangle CPQ given all sides by applying the Heron's formula for area of triangle which is;

A=√s(s-a)(s-b)(s-c)  where;

A=area of the triangle

s= half the perimeter of the triangle

a=side PQ = 2 units

b=side PC = 5 units

c= side QC = 3.6 units

Finding the perimeter of triangle CPQ will be;

P=sum of all sides

P=2+5+3.6 =10.6 units

s=10.6/2 = 5.3

Area of the triangle CPQ will be;

A=\sqrt{5.3(5.3-2)(5.3-5)(5.3-3.6)} \\A=\sqrt{5.3(3.3)(0.3)(1.7)} \\A=\sqrt{8.9} =2.98

A=3.0 (1 decimal place)

Compare the areas;

Area of triangle ABC=12 square units

Area of triangle CPQ = 3 square units

Area of triangle CPQ / Area of triangle ABC = 3/12 =1/4

Thus you have proved that area of triangle CPQ is 1/4 th area of triangle ABC because 1/4 *12 =3

Learn More

Area of a triangle ;brainly.com/question/14869984

The Heron's formula : brainly.com/question/10713495

Keywords: midpoint, triangle, sides, parallel, prove , area, equal

#LearnwithBrainly

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3 years ago
Find QR: 3x+22=10x-41
Tatiana [17]

Answer:

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Step-by-step explanation:

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Given that the contracts are awarded​ independently, find the probability that the company will get both contracts. recall ​p(la
VladimirAG [237]
If those percentiles are the changes of the two contracts occurring, it would be <span>0.31 *0.64 = </span>0,1984 

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saveliy_v [14]

Lines f and g look to be parallel to each other.

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