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pantera1 [17]
3 years ago
14

1457 divided by 12 Using long division to solve the following question

Mathematics
1 answer:
koban [17]3 years ago
8 0
Here’s a picture of you answer hopefully that helps ‍♀️

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An electrician disconnected 5 wires of different colors from their respective connections and forgot the order in which they wer
Inessa05 [86]

Answer:

120 tries

Step-by-step explanation:

You can try 5 different wires in the first connection.

Then you have 4 wires left, so you try 4 wires in the second connection. Remember, you are now trying 4 wires for each of the first 5, so up to here you already made 4 * 5 tries = 20 tries.

Next you try 3, then 2, then you have 1 left.

Number of tries: 5 * 4 * 3 * 2 * 1 = 120

Answer: 120 tries

8 0
3 years ago
0.9 0.947 1.5 1.268 in order from least to greatest
natka813 [3]
0.9 0.947 1.268 1.5 That's the order from least to greatest
3 0
2 years ago
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If you can pls answer any of these 6-10 plz do it would really help<br> (pic below)
Mariana [72]

Answer: the first one is $0.35

price per apple

5 0
3 years ago
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In the diagram below, m_MON = 1249, m _ MOP = 2x + 1, and m2 NOP = 2x
miv72 [106K]

Answer:

The answer is below

Step-by-step explanation:

The Angle Addition Postulate states that the measure of an angle formed by two or more angles which are placed side by side is the sum of the measures of the two angles.

Therefore:

∠MON = ∠MOP + ∠NOP (angle addition postulate)

Substituting values gives:

124 = (2x + 1) + (2x + 1)

124 = 2x + 2x + 1 + 1

124 = 4x + 2

subtracting 2 from both sides of the equation:

124 - 2 = 4x + 2 - 2

4x = 122

Dividing through by 4:

4x / 4 = 122 / 4

x = 30.5

Therefore ∠MOP = 2x + 1 = 2(30.5) + 1 = 62°, ∠NOP = 2x + 1 = 2(30.5) + 1 = 62°

∠MOP = 62°, ∠NOP = 62°

5 0
3 years ago
How do I do question 9 &amp; 11? Please help thank you!
Novay_Z [31]
<h2>9.</h2><h3>Given</h3>
  • sphere with radius 15 cm
<h3>Find</h3>
  • linear approximation to the volume when the radius increases 0.4 cm
<h3>Solution</h3>

The equation for volume of a sphere is

... V = (4/3)π·r³

Differentiating gives

... dV = 4π·r²·dr

Filling in the given numbers gives

... change in volume ≈ 4π·(15 cm)²·(0.4 cm)

... = 360π cm³ ≈ 1130.97 cm³ . . . . . . volume of layer 4mm thick

<h2>11.</h2><h3>Given</h3>
  • an x by x by 2x cuboid with surface area 129.6 cm²
  • rate of change of x is 0.01 cm/s
<h3>Find</h3>
  • rate of change of volume
<h3>Solution</h3>

The area is that of two cubes of dimension x joined together. The area of each such cube is 6x², but the two joined faces don't count in the external surface area. Thus the area of the cuboid is 10x².

The volume of the cuboid is that of two cubes joined, so is 2x³. Then the rate of change of volume is

... dV/dt = (d/dt)(2x³) = 6x²·dx/dt

We know x² = A/10, where A is the area of the cuboid, so the rate of change of volume is ...

... dV/dt = (6/10)A·dx/dt = 0.6·(129.6 cm²)(0.01 cm/s)

... dV/dt = 0.7776 cm³/s

5 0
3 years ago
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