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3 years ago

1 bag of pretzels cost four dollars. Five bags of pretzels cost $12.00. Which has the lower unit price??

Mathematics

2 answers:

devlian [24]3 years ago

7 0

Answer:

The second option

Step-by-step explanation:

In order to find the unit price of each, consider the quotient of amount of money per bag:

Case 1:

$4/ 1 bag

Case2:

$12 / 5 bags = $2.4 / 1 bag

Therefore, the second option is the one with lower unit price.

Rus_ich [418]3 years ago

5 0

Answer:

The 5 bags of pretzels.

Step-by-step explanation:

Because if you were to buy 5 individual bags you would end up paying $20.00, instead of $12.00

You might be interested in

What is the area of the composite shape

FrozenT [24]

Answer:

Step-by-step explanation:

The shape can be divided into two parts, let use the division in the question

So we have two rectangles

The area of a rectangle is given by l×b.

Let the big rectangle be 1

And the smaller rectangle be 2

Rectangle 1

Length is 16cm, breadth is 6cm

Area=l ×b

Area=16×6

Area=96cm^2

Rectangle two

The length will be 14-6=8cm

And the breadth will be 16-2=14cm

Then,

Area=l ×b

Area=14×8

Area=112cm^2

Total area is

Area1+Area2

112+96

Total area=208cm^2.

5 0

3 years ago

G= {(-5,5), (6, 8), (-5, -5)}<br> What is the domain and range

blagie [28]

Answer:

I'm pretty sure domain is x and range is why which would mean that:

domain: -5,6

range: 5,8,-5

Step-by-step explanation:

Hope this helps:)...if not then sorry for wasting you time and I hope you find the right answer and may God bless you:)

6 0

2 years ago

In 5 hours a small plane can travel downwind for 4000 kilometers or upward 3000 kilometers. Find the speed of this plane with no

Law Incorporation [45]

Answer:

discuss this question is about packhouse a small plant can travel 400 kilometre aur 2000 kilometre find the speed with a plan with no wind and a speed on the answer you will be given to you divide 5 400 the four hundred and 51 you divide the answer to get dawat 310 you will find the extra answer

4 0

3 years ago

Use the Trapezoidal Rule, the Midpoint Rule, and Simpson's Rule to approximate the given integral with the specified value of n.

Otrada [13]

I guess the "5" is supposed to represent the integral sign?

$I=\displaystyle\int_1^4\ln t\,\mathrm dt$

With $n=10$ subintervals, we split up the domain of integration as

[1, 13/10], [13/10, 8/5], [8/5, 19/10], ... , [37/10, 4]

For each rule, it will help to have a sequence that determines the end points of each subinterval. This is easily, since they form arithmetic sequences. Left endpoints are generated according to

$\ell_i=1+\dfrac{3(i-1)}{10}$

and right endpoints are given by

$r_i=1+\dfrac{3i}{10}$

where $1\le i\le10$ .

a. For the trapezoidal rule, we approximate the area under the curve over each subinterval with the area of a trapezoid with "height" equal to the length of each subinterval, $\dfrac{4-1}{10}=\dfrac3{10}$ , and "bases" equal to the values of $\ln t$ at both endpoints of each subinterval. The area of the trapezoid over the $i$ -th subinterval is

$\dfrac{\ln\ell_i+\ln r_i}2\dfrac3{10}=\dfrac3{20}\ln(ell_ir_i)$

Then the integral is approximately

$I\approx\displaystyle\sum_{i=1}^{10}\frac3{20}\ln(\ell_ir_i)\approx\boxed{2.540}$

b. For the midpoint rule, we take the rectangle over each subinterval with base length equal to the length of each subinterval and height equal to the value of $\ln t$ at the average of the subinterval's endpoints, $\dfrac{\ell_i+r_i}2$ . The area of the rectangle over the $i$ -th subinterval is then

$\ln\left(\dfrac{\ell_i+r_i}2\right)\dfrac3{10}$

so the integral is approximately

$I\approx\displaystyle\sum_{i=1}^{10}\frac3{10}\ln\left(\dfrac{\ell_i+r_i}2\right)\approx\boxed{2.548}$

c. For Simpson's rule, we find a quadratic interpolation of $\ln t$ over each subinterval given by

$P(t_i)=\ln\ell_i\dfrac{(t-m_i)(t-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+\ln m_i\dfrac{(t-\ell_i)(t-r_i)}{(m_i-\ell_i)(m_i-r_i)}+\ln r_i\dfrac{(t-\ell_i)(t-m_i)}{(r_i-\ell_i)(r_i-m_i)}$