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belka [17]
3 years ago
14

What is the point of intercection of lines y=x and y=2x+1

Mathematics
2 answers:
12345 [234]3 years ago
8 0

Answer:

(-1, -1)

Step-by-step explanation:

Let's set these two equations equal to each other to solve the system:

x = 2x + 1

Solving for x, we get x = -1

Plug this value of x back into any of the two equations to get y: y = 2 * (-1) + 1 = -1.

Thus, the point of intersection is (-1, -1).

Hope this helps!

mojhsa [17]3 years ago
6 0

Answer:

x = -1, y = -1

Step-by-step explanation:

y = 2x + 1

y = x

x = 2x + 1

x = -1

y = -1

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3 years ago
Z varies directly as x2. If z = 16 when x = 2, find z when x = 5.<br> ...<br> Z=
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Answer:

100

Step-by-step explanation:

it is a bit unclear to me, what that problem description means.

if I understand it correctly, than z is directly depending on x².

so, z = 16 for x = 2. x² = 4

I pondered a little bit, as there are several possibilities to connect 16 with 4 as a driving factor (e.g. 2⁴ = 16, 4×4 = 16, 12 + 4 = 16).

I decided to go with the simplest interpretation with the usual meaning of "varies" (multiplication) : 4×x²

that would mean

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3 years ago
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wel

the answer its -3/2

8 0
3 years ago
Read 2 more answers
Given that curl F = 2yi – 2zj + 3k, find the surface integral of the normal component of curl F (not F) over (a) the open hemisp
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Use Stokes' theorem for both parts, which equates the surface integral of the curl to the line integral along the surface's boundary.

a. The boundary of the hemisphere is the circle x^2+y^2=9 in the plane z=0, where the curl is \mathrm{curl}\vec F=2y\,\vec\imath+3\,\vec k. Green's theorem applies here, so that

\displaystyle\iint_S\mathrm{curl}\vec F\cdot\mathrm d\vec S=\int_{\partial S}\vec F\cdot\mathrm d\vec r=3\int_{x^2+y^2=9}\mathrm d\vec r

which means the value of the line integral is 3 times the area of the circle, or 27\pi.

b. The closed sphere has no boundary, so by Stokes' theorem the integral is 0.

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3 years ago
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