X/2 + 4 < 18

How to slove with systems of equations

juin [17]

Answer:

$3 for Syd and $5 for Mark

Step-by-step explanation:

when Mark worked 8 hours and Syd worked 10 hours they earned $80

when Mark worked 9h Syd worked 5h they earned $65

we can make a equation out of these information

8M + 10S = $80

9M + 5S = $65 we can use the systems of equations by eliminating method

multiply second equation by -2

-2 × (9M + 5S) = $65

-18M - 10S = -$130 now add up the new equation with the first one

8M + 10S - 18M - 10S = $80 - $130 (10S will eliminate -10S)

-10M = -$50

10M = $50

M = $5

we can use hourly rate we found for M (Mark) to find the hourly rate for S (Syd)

9×5 + 5S = $65

45 + 5S = $65

5S = $15

S = $3

8 0

3 years ago

I geologist note is that the land alone at fault line moved 24.8 cm over the past 175 years on average how much did the land mor

zmey [24]

First, let's establish a ratio between these two values. We'll use that as a starting point. I personally find it easiest to work with ratios as fractions, so we'll set that up:

$\frac{24.8\ cm}{175\ years}$

To find the distance per year, we'll need to find the unit rate of this ratio in terms of years. The word unit refers to the number 1 (coming from the Latin root uni- ); a unit rate involves bringing the number we're interested in down to 1 while preserving the ratio. Since we're looking for the distance the fault line moves every one year, we'll have to bring that 175 down to one, which we can do by dividing it by 175. To preserve our ratio, we also have to divide the top by 175:

$\frac{24.8\ cm}{175\ years}\div \frac{175}{175} \approx 
\frac{0.14\ cm}{1\ year}$

We have our answer: approximately 0.14 cm or 1.4 mm per year

3 0

3 years ago

Polygon ABCDE has the vertices A(2, 8), B(4, 12), C(10, 12), D(8, 8), and E(6, 6). Polygon MNOPQ has the vertices M(-2, 8), N(-4

Leto [7]

A transformation that can be performed on polygon ABCDE is a reflection over the y-axis.
The image of a polygon by a reflection its mirror image. The reflected image has the same size as the original.
It means that polygon ABCDE is congruent to polygon MNPQ.

9 0

2 years ago

Find the value of x I really need this to pass this yr.

svp [43]

It takes a while to see through this one.
I think that's because the triangle is in a weird position.

The arrows on the two across-lines tell us that those lines are parallel.
And THAT tells us that the two triangles are similar ... the whole big triangle,
and the smaller triangle on the bottom.

If two triangles are similar, then what ?

-- Their corresponding angles are equal. That doesn't help us in this problem.

-- Their corresponding sides are in the same ratio. That helps us a lot !

The left side of the big triangle = 5 + 8 = 13
The left side of the small triangle = 8

Now we know that corresponding sides of the two triangles
have the ratio of 13 to 8 .

The right side of the big triangle = 4 + x
The right side of the small triangle = x

The ratio has to be 13/8 , so ===> (4+x) / x = 13 / 8 .

That's the tough part. Now you take it and finish it off from here.

8 0

3 years ago

Can someone please help even bubbling in with no work is ok I just don’t understand.

Ronch [10]

Answer:

This is as much as I could do.

Step-by-step explanation:

Steps r in pic below

8 0

3 years ago