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nikdorinn [45]
3 years ago
15

A line passes through (−2, 5) and has slope 13 . What is an equation of the line in point-slope form

Mathematics
1 answer:
ruslelena [56]3 years ago
3 0
Y - y1 = m(x - x1)
slope(m) = 13
(-2,5)...x1 = -2 and y1 = 5
sub...pay attention to ur signs
y - 5 = 13(x - (-2)...not done yet
y - 5 = 13(x + 2) <== point slope form
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Find the median of the following set of data:
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Answer:

b

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Arrange the data in ascending order

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The median of the data set is 57 → b

3 0
3 years ago
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viva [34]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
Which equation represents the line that passes through the points (6,-3) and (-4,-9)?
Citrus2011 [14]
I will give in y=mx+b and ax+by=c form

using point slope form
y-y1=m(x-x1)
where the slope is m and a point on that line is (x1,y1)

slope between 2 points (x1,y1) and (x2,y2) is (y2-y1)/(x1-x1)

given
(6,-3) and (-4,-9)
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a point is (6,-3)

y-(-3)=3/5(x-6)
y+3=3/5(x-6)
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7 0
3 years ago
What are the 1st and 3rd quartiles?<br> what is the interquartile range?
FrozenT [24]

Answer:

The first quartile is 5

The third is 8

The interquartile is the difference between the first and third quartile.

The interquartile is 3

Step-by-step explanation:

First, make a list of all the numbers. To find the first quartile, you have to first find the median. The median is the first 7 in the list.

Everything before 7 is the lower percentile of the range.

The firsr quartile is the median of the lower percentile.

The lower list is:

2,3,4,4,5,6,6,6

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The process for finding the third quartile is the same except the list is the higher percentile which is the list of numbers above the median.

7 0
2 years ago
Read 2 more answers
√12 + √10 − √2) is
r-ruslan [8.4K]

Hello!

\bf  \sqrt{12}  + \sqrt{10}  -  \sqrt{2} =

\bf  \sqrt{ {2}^{2}  \times 3}  +  \sqrt{10}  -  \sqrt{2}  =

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\bf \boxed{ 2  \sqrt{3}  +  \sqrt{10}  -  \sqrt{2}}

Answer: (c) An irrational number

Good luck! :)

5 0
3 years ago
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