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tankabanditka [31]
2 years ago
11

Do number 11 please

Mathematics
1 answer:
Stels [109]2 years ago
7 0
Answer is A,
multiply 12.50 with 70 and multiply 8.75 with 15. Then add the products together.
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I need the answer urgently plz
frozen [14]
To find the length of the base, you must first find the length of the sides, or the value of x. Because it is an isosceles triangle, the legs are equal to each other. 

2x + 4=x + 8
x=4

Now that you have found x, plug it into the equation for the base. 

5(4) - 2
20 - 2
18
Final Answer: 18

Hope this helps!! :)




8 0
4 years ago
Add. 5/6 + 2 3/4 in simplest form.
Deffense [45]

okay so you would first turn everything into fractions 2 3/4= 11/4 + 5/6

next you would change the denominators so they match 11/4 x 6 = 66/24

5/6 x 4 = 20/24

so then you would add 66/24 + 20/24 = 88/24 = 11/3

11/3 is your answer



hope this helps!


7 0
4 years ago
A committee is formed from seniors, juniors, sophomores, and freshman. All students are seated around a circular table. If stude
Ahat [919]
Well just do 4 groups *4*4*4*4
5 0
3 years ago
Need help with these 3
Tamiku [17]

Answer:

1.) x = 110

\frac{3}{22} =\frac{15}{x}

So for 3 to become 15 it would have to be multiplied by 5 because 3 x 5 = 15. And if I multiply the numerator by anything I always have to do the same to the denominator. So I multiply 22 x 5 = x. x = 110

\frac{3 * 5}{22*5} =\frac{15}{110}

2.) x = 72

\frac{x}{16} =\frac{9}{2}

For 16 to become 2 it has to be divided by 8 because 16 ÷ 8 = 2. And I have to do the same to the numerator of course, so i have to find x ÷ 8 = 9. I know the answer by memory, but for some it's easier to rewrite this as 9 × 8 = x. x=72

\frac{72}{16} =\frac{9}{2}

3.) c = 24

\frac{3}{5} =\frac{c}{40}

For 5 to become 40 it must be multiplied by 8 because 5 × 8 = 40. I have to multiply 8 by the numerator as well and 3 × 8 = 24. c = 24

\frac{3*8}{5*8} =\frac{24}{40}

5 0
3 years ago
Read 2 more answers
Consider the inverse function. Which conclusions can be drawn about f(x) = x2 + 2? Select three options. f(x) has a limited rang
PolarNik [594]

Answer:

f(x) has a limited range

f(x) has a maximum at the point (0, 2)

f(x) has a y-intercept at the point (0, 2).

Step-by-step explanation:

Given the function;

f(x) = x^2+2

The domain is the value of the input variables for which the function will exist. According to the expression given, the function exists on all real values of x. The same goes with range which deals with the output values. It also exists on all real values from 2 and above.

Hence f(x) have a limited range (since values less than 2 are not included compare to domain that exists on all real values) and does not have a restricted domain.

For the x intercept, x intercept occur at y = 0

substitute y = 0 into the function and get y

if y = f(x)

y = x^2+2

0 = x^2 + 2

x^2 = -2

x = 2i

Hence  f(x) does not have an x-intercept of (2, 0)

For the y intercept, y intercept occur at x = 0

substitute x = 0 into the function and get y

if y = f(x)

y = x^2+2

y = 0^2 + 2

y = 2

Hence  f(x) has a y-intercept at point (0, 2)

f(x) is at maximum if d(fx))/dx = 0

d(fx))/dx  = 2x

since  d(fx))/dx  = 0

0 = 2x

x = 0

substitute x = 0 into the function

f(x) = x^2 + 2

y = 0^2+2

y = 2

Hence f(x) has a maximum at the point (0, 2)

5 0
3 years ago
Read 2 more answers
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