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tankabanditka [31]
2 years ago
11

Do number 11 please

Mathematics
1 answer:
Stels [109]2 years ago
7 0
Answer is A,
multiply 12.50 with 70 and multiply 8.75 with 15. Then add the products together.
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A rotation maps point A to A’.
weeeeeb [17]

Answer:  The answer is (C) 180° rotation.

Step-by-step explanation:  Given that the point A maps to the point A' by a rotation. We are to select the statement that describes the rotation.

In the given figure, the co-ordinates of point A are (-3, 5) and after rotation, the co-ordinates of point A' are (3, -5).

Therefore, the point (x, y) changes to (-x, -y) after rotation. This is the result of 180° rotation.

Therefore, the point A is rotated through an angle of 180° to reach at the point A'.

Thus, the correct option is (C) 180° rotation.

5 0
3 years ago
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What's the square root of 1331 to the third power
ivanzaharov [21]

Answer:

48559 if to the nearest whole number

48558.7 if to the nearest tenth

8 0
3 years ago
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6) 8x+y=-16<br> -3x+y=-5<br> Solve each system by elimination?
Anarel [89]

Answer:

x=-2.2 y=-1.6

Step-by-step explanation:

8x+y=-16

-3x+y=5

5x=-11

x=-11/5 or -2.2

-3x+y=5

-3(-2.2)+y=5

6.6+y=5

-6.6+y=-6.6

y=-1.6

4 0
3 years ago
Can somebody plz help answer this word problem using equations thx :3 (only if u done this before) lol :)
ycow [4]

Answer:

one num = 6

another = 24

Step-by-step explanation:

One number = x

Another = 4x

Difference = 18

4x - x = 18

3x = 18 ; x = 18/3 = 6

8 0
3 years ago
Simplify the problem: Sin theta Sec Theta
kherson [118]

Answer:

\tan \theta

Step-by-step explanation:

We have to simplify the following expression as given by

\sin \theta \times \sec \theta

= \frac{\sin \theta}{\cos \theta}

= \tan \theta ( Answer )

Because, we know that \sec \theta =\frac{1}{\cos \theta} and \tan \theta = \frac{\sin \theta}{\cos \theta}

If we consider \sin \theta = \frac{Perpendicular}{Hypotenuse} and \sec \theta = \frac{Hypotenuse}{Base},

then \sin \theta \times \sec \theta = \frac{Perpendicular}{Hypotenuse}\times \frac{Hypotenuse}{Base} = \frac{Perpendicular}{Base}= \tan \theta

3 0
3 years ago
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