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exis [7]
3 years ago
7

The posted weight limit for a wooden

Mathematics
1 answer:
artcher [175]3 years ago
5 0

9514 1404 393

Answer:

  186

Step-by-step explanation:

Let b represent the number of boxes in the truck. Then for the weight limit to be met, we require ...

  3512 +16b < 6500

  16b < 2988

  b < 186.75

The maximum number of boxes is 186.

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A can holds 753.6 cubic centimetres of juice the can has a diameter of 8 centimeters what is the height of the can
aleksklad [387]

Answer:

about 30 cm

because if the can, can hold 753.6 Cubic Centimeters of juice and has the diameter of 8 the height would be 30

6 0
4 years ago
15% discount saves you $5 off the price of an electronic game. How much do you save off the regular price if the discount is rai
Readme [11.4K]

The answer is $15. If you need an explanation tell me .

IF I GOT IT RIGHT PLEASE THANK ME, AND GIVE ME BRAINLIEST =)

If 15% gives you $5 off. Your trying to find out how much $$$ you will get off with a 45% discount. 15% times 3 is 45%. So you need to do three times $5, because both sides need to have the same things done to them. $5 times three is $15.

15% x 3 = 45%    $5 x 3 = $15

5 0
3 years ago
I need help with this please​
lukranit [14]

Answer:

  \textbf{D.  }\overrightarrow{BA}

Step-by-step explanation:

The end point of a ray is named first. The name of another point on the ray completes the ray name. Any arrow over the name will be single ended, with its tail over the name of the endpoint.

A ray with endpoint B will be B[something] with an over-arrow pointing to the right:

  \overrightarrow{BA}

8 0
3 years ago
A 500.0 g piece of aluminum at 100° C is placed in 300ml of water. While in the water, the
Orlov [11]

Answer:

The amount of heat lost by the aluminum is 31,500 J

Step-by-step explanation:

Given;

mass of aluminum, m =  500 g

initial temperature of the aluminum, θ₁ = 100° C

final temperature of the aluminum, θ₂ = 30°C

specific heat capacity of water, C = 4.18 J/g °C

specific heat capacity of aluminum , C = 0.90 J/g

Heat lost by the aluminum is equal to heat gained by the water.

The amount of heat lost by the aluminum, is calculated as;

Q = MCΔθ

Q = 500 x 0.9 (100 - 30)

Q = 500 x 0.9 x 70

Q = 31,500 J

Therefore, the amount of heat lost by the aluminum is 31,500 J

7 0
4 years ago
How to solve 7x-5=6x-4
sergejj [24]

Answer: x =1

Step-by-step explanation: 7x-5=6x-4

7x=6x+1

x=1

5 0
3 years ago
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