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3 years ago

How were Renaissance artists able to support themselves and their work?

Mathematics

2 answers:

bonufazy [111]3 years ago

8 0

Answer:

Artists in this time were very well respected, unlike the olden times, the practice of art flourished during this time.

Step-by-step explanation:

9966 [12]3 years ago

4 0

Answer: Artists carried a special status in Renaissance society. They were respected; they were admired; they were practically worshiped.

Step-by-step explanation: High Renaissance (1475-1525) - A rising interest in perspective and space gave the art even more realism. Great artists such as Michelangelo, Leonardo da Vinci, and Rafael flourished during this period.

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Someone help me please

kherson [118]

Answer:

I will just choosé the second one

Because it is possible to compare sizes In one triangle rather than comparing with another one which we don't reàlly know of its sizes.

4 0

2 years ago

Question 2.

ipn [44]

Answer:

1) -0.669

2) -0.669

3) 0.669

Step-by-step explanation:

Since we are subtracting or adding multipled of pi, we will either obtain 0.669 or -0.669 as our answer for each of the three different questions.

Cosine is the x-coordinate in our orderes pairs. If our point ends up on the right side of the y-axis, the cosine will be positive. If our point ends up on left side, it will be negative.

Choose a thetha (I'm going to choose it in degrees) in the first quadrant to help with a visual.

If theta=70:

1) then 180-70=110 which is in second quadrant, so our cosines will be opposite in value.

2) then 180+70=250 which is in third quadrant, so our cosines will be opposite in value.

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3 0

3 years ago

Implicit differentiation Please help

Anvisha [2.4K]

Answer:

$y''(-1) =8$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Algebra I

Factoring

Calculus

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Quotient Rule: $\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

-xy - 2y = -4

Rate of change of the tangent line at point (-1, 4)

Step 2: Differentiate Pt. 1

Find 1st Derivative

Implicit Differentiation [Product Rule/Basic Power Rule]: $-y - xy' - 2y' = 0$
[Algebra] Isolate y' terms: $-xy' - 2y' = y$
[Algebra] Factor y': $y'(-x - 2) = y$
[Algebra] Isolate y': $y' = \frac{y}{-x-2}$
[Algebra] Rewrite: $y' = \frac{-y}{x+2}$

Step 3: Find y

Define equation: $-xy - 2y = -4$
Factor y: $y(-x - 2) = -4$
Isolate y: $y = \frac{-4}{-x-2}$
Simplify: $y = \frac{4}{x+2}$

Step 4: Rewrite 1st Derivative

[Algebra] Substitute in y: $y' = \frac{-\frac{4}{x+2} }{x+2}$
[Algebra] Simplify: $y' = \frac{-4}{(x+2)^2}$

Step 5: Differentiate Pt. 2

Find 2nd Derivative

Differentiate [Quotient Rule/Basic Power Rule]: $y'' = \frac{0(x+2)^2 - 8 \cdot 2(x + 2) \cdot 1}{[(x + 2)^2]^2}$
[Derivative] Simplify: $y'' = \frac{8}{(x+2)^3}$