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Roman55 [17]
3 years ago
14

What is the mass of 2.5 moles of carbon dioxide?

Mathematics
1 answer:
GarryVolchara [31]3 years ago
3 0

Answer:

110 grams

Step-by-step explanation:

CO2 molecule is made up of Carbon (atomic mass =12) and oxygen (atomic mass=16).

So first finding the mass of 1 molecule of CO2 which is equals to

= mass of 1 carbon atom + masses of 2 oxygen atom, we get

= 12+(16*2)= 12+32= 44 a.m.u.

Now 1 molecule of CO2 has mass 44 amu so mass of 1 mole CO2 will be 44 grams.( 1 a.m.u.=1.6729*10^-33 grams. 1 mole = 6.022*10^23, so 44 a.m.u.=73.6076*10^-33 grams approx. For one mole CO2, 73.6076*10^-33*6.022*10^23 which is approximately equals to 44 grams. )

1 mole CO2= 44grams, so 2.5 moles = 44*2.5= 110 grams

So our answer is 110 grams.

lowkey hope this helped you, good luck whatever you need it for Imaooo

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4. The stock market goes up more often that it goes down. Assume the probability that the stock market goes up in a randomly sel
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Answer:

a: 0.0022

b: 0.00002

c: 0.0002

d: 924

e:  0.0025

f: 0.6652

g:  Expected value 7.8 months, standard deviation 1.77 months

Step-by-step explanation:

This is a binomial situation.  Either the market goes up, or it doesn't.  (It could stay the same, but it doesn't offer that as an option, so we don't include it).

When calculating probability of a binomial situation, use the formula

(nCr)(p^r)(q^(n-r))   where p is the probability of success, q is the probabilty of failure, n is the the number of times the situation occurs, and r is the desired number of successful outcomes.  The function nCr tells us how many ways you can choose r items from n total items.  In this case, we are choosing some number of months, r, from 12 months, n

For our situation we have:  n = 12, r = 12, p = 0.6, q = 0.4,

For a:   (12C12)(0.6^12)(0.4^0) = (1)(0.0022)(1) = 0.0022

We want all 12 months of success and no months of failure

For b:   (12C0)(0.6^0)(0.4^12) = (1)(1)(0.00002) = 0.00002

We want all months of failure, and no months of success

For c:   (0.6^6)(0.4^6) = 0.0002

We don't need the nCr function because it tells us that it we want 6 months of success followed by 6 months of failure.  There's only 1 way to do that, so there's nothing to count

For d:  12C6 = 924  

There are 924 different ways to the market can go up 6 times out of 12 months

For e:  (12C2)(0.6^2)(0.4^10) = (66)(0.36)(0.0001) = 0.0025

For f:  Add the following probabilities together...

(12C7)(0.6^7)(q^5) + (12C8)(0.6^8)(q^4) + (12C9)(0.6^9)(q^3)

+ (12C10)(0.6^10)(q^2) + (12C11)(0.6^11)(q^1) + (12C12)(0.6^12)(q^0)

= 0.6652

They are mutually exclusive, the probability for the union is zero because they can't happen at the same time

For g:  Find expected value with the formula E = np  , here n = 12, p = 0.6, so

E = 12(0.6) = 7.8 months

Find the standard deviation with the formula s = √(npq), or s = √(Eq), here q = 0.4, so s = √(7.8(0.4)) = 1.77 months

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