Oh. It's rounding. So, for example, depending what you were told to round to, the second problem would be 760-330=430
Answer:
y=ln(x/(1-x))
Step-by-step explanation:
y=e^x/(1+e^x)
Cross multiply
y(1+e^x)=e^x
Distribute
y+ye^x=e^x
Put anything with x on with side and everything without x on opposing side:
y=e^x-ye^x
Factor right hand side
y=(1-y)e^x
Divide both sides by (1-y)
y/(1-y)=e^x
Use natural log.
ln(y/(1-y))=x
The inverse is
y=ln(x/(1-x))
16.4
20.5/5=4.1
4.1*4=16.4
............
<h3>Given:</h3>
- P= $50,000
- R= 10%
- T= 5 years
<h3>Note that:</h3>
- P= Principal amount
- R= Rate of interest
- T= Time period
<h3>Solution:</h3>

Let's substitute according to the formula.

<em>A=</em><em> </em><em>$80525.5</em>
Now, we can find the interest paid

We'll have to deduct the total amount from the principal amount.
Let's substitute according to the formula.

<em>I=</em><em> </em><em>$30525.5</em>
<u>Hence</u><u>,</u><u> </u><u>the</u><u> </u><u>total</u><u> </u><u>amount</u><u> </u><u>paid</u><u> </u><u>after</u><u> </u><u>5</u><u> </u><u>years</u><u> </u><u>is</u><u> </u><u>$</u><u>80525.5</u><u> </u><u>and</u><u> </u><u>$</u><u>30525.5</u><u> </u><u>was</u><u> </u><u>paid</u><u> </u><u>as</u><u> </u><u>interest</u><u>.</u>
Answer:
it is not necessary to confirm that the sample data appear to be from a population with a normal distribution;
D. Because the sample size of 50 is greater than 30, it can be assumed that the sample mean is from a population with a normal distribution
Step-by-step explanation:
Normal distribution which is otherwise known as the Gaussian distribution, it is a probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean.
The arithmetic mean or average; is the sum of a collection of numbers divided by the total numbers in the collection.