thirty-seven point five percent and three per eight
Let t = the number of days the mouse travels
Let D = the distance that the mouse traveled
The mouse travels at a rate of 1.5 miles per day, so R = 1.5 mi/day
The equation is:
Distance (D) = Rate (R) x Time (t)
SO:
Distance (D) = 1.5 mi./day X Time (t)
The formula that is useful for solving both of these problems is ...

9. Given v₁=15, a=9.8, d=10, find v₂.
... (v₂)² = 15² + 2·9.8·10
... v₂ = √421 ≈ 20.5 . . . . m/s
10. Given d=12 m when a=-9.8 m/s² and v₂=0, find d when a=0.17·(-9.8 m/s²).
The formula tells us that d=(v₁)²/(2a), which is to say that the distance is inversely proportional to the acceleration. If acceleration is 0.17 times that on earth, distance will be 1/0.17 ≈ 5.88 times that on earth.
(12 m)/0.17 ≈ 70.6 m
3/10 of the time = time spent on practicing warm up routines...
Time spent = 15 hours
remember that 'of' is usually multiply (x)
so ---- 3/10 x 15 =4.5 hrs
Hope this helps
Answer:
D. Keep track of the number of heads flipped in 50 flips. These represent the number of females born today. Repeat this 200 times.