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mr Goodwill [35]
3 years ago
6

The temperature in Fargo was (-28) degrees on Monday afternoon. By the evening it dropped an additional 15 degrees. What was the

temperature in the evening.
Please do this quick this is due in 5 minutes btw please show step by step and this is integers word problem
Mathematics
1 answer:
antiseptic1488 [7]3 years ago
7 0

Step by step explanation: -28-15

When adding negative with positive it will always be negative so for this question, subtract -28 with 15 which would be -48. So -48 would be the temperature in the evening.

Final Result: -43

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Please solve this in 2 parts as stated... thank you!
fredd [130]

Solve the equation we have that:

a. S = 3V²/ 4

b. S = 108 feet

<h3>How to solve the parameters?</h3>

We have the equation to be;

V = 2√3S

Where;

  • V is the speed
  • S is the length

Let's make S the subject from the formula, divide both sides by 2√2S = v/ 2. Take square of both sides:

(\sqrt{3S} )^2 = \frac{V^2}{4}\\3S = \frac{V^2}{4}

Now we need to divide both sides by three:

S = 3V²/ 4

b. If v = 12miles per hour, substituting in the equation found earlier:

S = 3 (12²)/ 4

S= 432/ 4

S = 108 feet

Thus, the formula for the length is S = 3V²/ 4

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4 0
1 year ago
A freshly inoculated bacterial culture of Streptococcus contains 100 cells. When the culture is checked 60 minutes later, it is
Luba_88 [7]

Answer:

P(t) = 100e^{0.0251t}

The doubling time is of 27.65 minutes.

Step-by-step explanation:

Exponential equation of growth:

The exponential equation for population growth is given by:

P(t) = P(0)e^{kt}

In which P(0) is the initial value and k is the growth rate.

A freshly inoculated bacterial culture of Streptococcus contains 100 cells.

This means that P(0) = 100. So

P(t) = 100e^{kt}

When the culture is checked 60 minutes later, it is determined that there are 450 cells present.

This means that P(60) = 450, and we use this to find k. So

450 = 100e^{60k}

e^{60k} = 4.5

\ln{e^{60k}} = \ln{4.5}

60k = \ln{4.5}

k = \frac{\ln{4.5}}{60}

k = 0.0251

So

P(t) = 100e^{0.0251t}

Doubling time:

This is t for which P(t) = 2P(0) = 200. So

200 = 100e^{0.0251t}

e^{0.0251t} = 2

\ln{e^{0.0251t}} = \ln{2}

0.0251t = \ln{2}

t = \frac{\ln{2}}{0.0251}

t = 27.65

The doubling time is of 27.65 minutes.

7 0
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True [87]
The figure is a rectangle so the formula is area = length *width

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Answer:

Step-by-step explanation:

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