X^2 - 4x + 2
d = b^2 - 4ac, where a = 1, b = -4 and c = 2
d = (-4)^2 - 4 x 1 x 2
d = 16 - 8
d = 8
Assuming the exponent is supposed to be "^2" your equation will read:
4x² + 8x - 5
It must set equal to y to be a valid function and the y must be set equal to zero to find x-intercepts.
4x² + 8x - 5 = 0
4x² - 2x + 10x - 5 = 0
2x(2x - 1) + 5(2x - 1) = 0
(2x + 5)(2x - 1) = 0
Set each binomial equal to zero.
2x + 5 = 0
2x = 0 - 5
2x = - 5
Divide both sides by 2
x = - 5/2
2x - 1 = 0
2x = 0 + 1
2x = 1
x = 1/2
Your x-intercepts are x = - 5/2, 1/2 or (- 5/2, 0) and (1/2, 0)
Answer:
C
Co efficient means the number or value beside preventing the variable from standing alone
Sounds as tho' you have an isosceles triangle (a triangle with 2 equal sides). If this triangle is also a right triangle (with one 90-degree angle), then the side lengths MUST satisfy the Pythagorean Theorem.
Let's see whether they do.
8^2 + 8^2 = 11^2 ???
64 + 64 = 121? NO. This is not a right triangle.
If you really do have 2 sides that are both of length 8, and you really do have a right triangle, then:
8^2 + 8^2 = d^2, where d=hypotenuse. Then 64+64 = d^2, and
d = sqrt(128) = sqrt(8*16) = 4sqrt(8) = 4*2*sqrt(2) = 8sqrt(2) = 11.3.
11 is close to 11.3, but still, this triangle cannot really have 2 sides of length 8 and one side of length 11.
