3 years ago

Can anyone answer this pleaseee

Mathematics

1 answer:

77julia77 [94]3 years ago

8 0

Answer:

Step-by-step explanation:

the 1st choice , Kim, looks good

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Answer:

1. 25

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3 years ago

Solve 2cos x+2cos 2x=0 on the interval [0,2pi)

rjkz [21]

$2cosx+2cos2x=0 \\ -2sin^2x+2cos^2x+2cosx=0 \\ -2(1-cos^2x)+2cos^2x+2cosx=0 \\ -2+2cos^2x+2cos^2x+2cosx=0 \\ 4cos^2x+2cosx-2=0 \\ t=cos x \\ 4t^2+2t-2=0 \\ \Delta=4+32=36 \\ t_1= \frac{-2-6}{8}=-1 \\ t_2= \frac{-2+6}{8}= \frac{1}{2} \\ cos x=-1 \lor cos x= \frac{1}{2} \\ x=-\pi \lor x= \frac{5\pi}{3}$

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3 years ago

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Rzqust [24]

Step-by-step explanation:

1.n:1

6:8

2.cross multiply

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3 years ago

Quadrilateral BCDE is inscribed in circle A. The measure of ⏜ is 73°. The measure of ⏜ is 53° and the measure of ⏜ is 102°. Dete

Anton [14]

Answer: c

Step-by-step explanation:

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3 years ago

Which of the following can be calculated using formula C= 2πr

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Hello!

In this formula, C represents the circumference, as pi and r, the radius are in the equation. 2r is also equal to the diameter.

The answer is the circumference.

Hope this helps!

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3 years ago

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