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Yuri [45]
3 years ago
9

Find the measure of each angle and classify the triangle accordingly. In triangle ABC, measure of angle A = 2(measure of angle B

) and measure of angle C = 3(measure of angle B).
Mathematics
1 answer:
Eduardwww [97]3 years ago
5 0

Answer:

The measure of each angle of Triangle is

∠ A = 60° ,

∠ B  =  30° ,

∠ C = 90°

Step-by-step explanation:

Given as in a triangle :

The three angles of Triangle are

∠ A , ∠ B , ∠ C

∠ A = 2 ×  ∠ B

∠ C =  3 ×  ∠ B

Now, <u>From the property of Triangle</u>

The sum of all the three angles of Triangle is 180°

So, ∠ A + ∠ B + ∠ C =  180°

Or, ( 2 ×  ∠ B ) + ∠ B +  (  3 ×  ∠ B ) =  180°

Or,  6 ×  ∠ B  =  180°

∴     ∠ B  =  \frac{180}{6}

So,  ∠ B  =  30°

And , ∠ A = 2 ×  ∠ B = 2 ×  30°

So,    ∠ A = 60°

Similarly , ∠ C =  3 ×  ∠ B = 3 ×  30°

So,      ∠ C = 90°

Hence The measure of each angle of Triangle is ∠ A = 60° , ∠ B  =  30° ,

∠ C = 90°  Answer

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Answer:

X = 4

Step-by-step explanation:

In the equation add 3 to both sides of the equation

1/2x-3+3=2-3/4x+3

Simplify

1/2x = -3/4x + 5

Add 3/4x to both sides

1/2x + 3/4x = -3/4x + 5 + 3/4x

Simplify

5/4x=5 Multiply both sides by 5

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5 0
3 years ago
Pls help i really really need help on this. We just learned this but i can't remember it.
bulgar [2K]

Answer:

114 cm²

Step-by-step explanation:

Area of shaded region

= area of circle -area of square

\boxed{area \: of \: circle = \pi {r}^{2} }

Given that radius= 10cm, r= 10cm.

\boxed{area \: of \: square = side \:  \times side}

Let the length of a side of the square be x cm.

Applying Pythagoras Theorem,

10² +10²= x²

100 +100= x²

x²= 200

x =   \sqrt{200}

Area of square

= x²

= 200cm²

Area of shaded region

= 3.14(10²) -200

= 3.14(100) -200

= 314 -200

= 114 cm²

8 0
2 years ago
Does anyone know how to solve this?
Olegator [25]

m=70/2=35

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3 years ago
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C
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