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3 years ago

Why does the body need nitrogen compounds?

Chemistry

2 answers:

castortr0y [4]3 years ago

6 0

Answer:

To make proteins....

It is used to make amino acids in our body which in turn make proteins.

Explanation:

hope it was helpful.....

Nostrana [21]3 years ago

4 0

To make carbohydrates

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How many magnesium ions are present in 5.36 x 10-4 mol of magnesium iodide?

WARRIOR [948]

Magnesium iodide = MgI₂
mass of Mg = 24.3g
mass of I = 126.9g
mass of MgI₂ = 24.3 + 2*126.9 = 278.1g = 1 mole

in 5.36x10⁻⁴ mole of MgI₂ ---------------- x g of Mg
in 1 mole of MgI₂ ------------------------------ 1 mole of Mg
x = 5.36x10⁻⁴ moles of Mg = 0.000536 moles of Mg

answer: we've 0.000536 moles of Mg (magnesium ions) in 5.36x10⁻⁴ moles of MgI₂

4 0

4 years ago

if 25 g of potassium nitrate hydroxide reacts with 25bg of magneisum nitartae to produce potassium nitrate and magneisum hydroxi

Natasha_Volkova [10]

Answer:

0.336 moles of KNO₃ are produced

The limiting reactant is Mg(NO₃)₂

Explanation:

We need to define the reaction to complete this question:

Reactants are: KOH and Mg(NO₃)₂

Products are: KNO₃ and Mg(OH)₂

The reaction is:

2KOH + Mg(NO₃)₂ → 2KNO₃ + Mg(OH)₂

We convert the mass of the reactants, to moles:

25 g / 56.1 g/mol = 0.446 moles

25 g / 148.3 g/mol = 0.168 moles

2 moles of hydroxide need 1 mol of nitrate to react

Then, 0.446 moles of KOH must need (0.446 .1) / 2 = 0.223 moles of nitrate

We do not have enough nitrate, so the Mg(NO₃)₂ is the limiting reagent.

Let's work with the equation and the ratio, which is 1:2

1 mol of Mg(NO₃)₂ produces 2 moles of KNO₃

Then, 0.168 moles of Mg(NO₃)₂ will produce (0.168 . 2) / 1 = 0.336 moles of KNO₃ are produced

5 0

3 years ago

how many moles of hydrogen gas will be produced if you start with 2.5 moles of magnesium and an excess of hydrochloric acid give

Vinil7 [7]

Number of moles of Hydrogen gas produced = 2.5 moles

Given the balanced chemical equation,

$Mg+2HCl \rightarrow MgCl_2+H_2$

This means, 1 mole of Mg and 2 moles of HCl gives 1 mole of Hydrogen gas.

Given that 2.5 moles of Magnesium is taken and an excess of Hydrochloric acid.

The mole ratio of Magnesium and Hydrogen = 1:1

Thus 2.5 moles of Magnesium with an excess of Hydrochloric acid will yield 2.5 moles of Hydrogen gas.

[By referring excess of HCl, we may assume that it contains at least 5 moles of HCl. Then only 2.5 moles of Mg will produce 2.5 moles of Hydrogen gas].

Learn more about the mole ratio at brainly.com/question/19099163

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6 0

2 years ago

Which one of the following solutions will have the greatest concentration of hydroxide ions?

jek_recluse [69]

Answer:

e = 0.250 M calcium hydroxide

it will produce 0.5 M [OH⁻].

Explanation:

A = 0.100 M HCl

HCl is an acid it would produce negligible amount of OH⁻.

B = 0.100 M magnesium hydroxide

Mg(OH)₂ + H₂O → Mg²⁺ + 2OH⁻

The ration of Mg(OH)₂ and OH⁻ is 1:2.

[OH⁻] = 2× 0.100 = 0.200 M

C =0.100 M ammonia

NH₃ + H₂O → NH₄OH → NH₄⁺ + OH⁻

The Kb expression will be written as,

Kb = [NH₄⁺] [OH⁻] / [NH₃]

Kb = 1.8 ×10 ⁻⁵

Now we will put the values:

1.8 ×10 ⁻⁵ = [NH₄⁺] [OH⁻] / 0.100

[NH₄⁺] [OH⁻] = x²

1.8 ×10 ⁻⁵ = x² / 0.100

x² = 1.8 ×10 ⁻⁵ × 0.100

x² = 1.8 × 10 ⁻⁶

x = 1.34 × 10 ⁻³

[OH⁻] = 1.34 × 10 ⁻³ M

d = 0.300 M rubidium hydroxide

RbOH + H₂O → Rb⁺ + OH⁻

The ratio of RbOH and OH⁻ is 1:1.

[OH⁻] = 0.300 M

e = 0.250 M calcium hydroxide

Ca(OH)₂ + H₂O → Ca²⁺ + 2OH⁻

The ration of Ca(OH)₂ and OH⁻ is 1:2.

[OH⁻] = 2× 0.250 = 0.5 M

7 0

3 years ago

to save time you can approximate the initial volume of water to ±1 ml and the initial mass of the solid to ±1 g . for example, i

makkiz [27]

The correct answer for this question is

20.2 g silver placed in 21.6 mL of water and 12.0 g silver placed in 21.6 mL of water.

15.2 g copper placed in 21.6 mL of water and 50.0 g copper placed in 23.4 mL of water.

11.2 g gold placed in 21.6 mL of water and 14.9 g gold placed in 23.4 mL of water.

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8 0

2 years ago