There is one atom in a Monoatomic Ion whereas Many in Polyatomic.
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Answer:
We have to add 17.2 grams of aluminium bromide
Explanation:
Step 1: Data given
Molarity of the aluminum bromide solution = 0.215 M
Volume = 300 mL = 0.300 L
Molar mass aluminium bromide = 266.69 g/mol
Step 2: Calculate moles Aluminium bromide
moles AlBr3 = volume * molarity
Moles AlBr3 = 0.300 L * 0.215 M
Moles AlBR3 = 0.0645 moles
Step 3: Calculate mass aluminium bromide
Mass aluminium bromide = moles AlBr3 * molar mass AlBr3
Mass aluminium bromide = 0.0645 moles * 266.69 g/mol
Mass aluminium bromide = 17.2 grams
We have to add 17.2 grams of aluminium bromide
Answer:
<h2>1. precede emotional experience</h2><h2>2. occur at the same time</h2>
Explanation:
William James and Carl Lange gave a theory about a type of emotion is called a James-Lange theory. According to this theory, physiological arousal creates an emotional experience. According to this theory, physiological changes are the primary condition while emotion is felt when brain interacts with the information obtained from the body.
According to the Cannon-Bard theory, the emotional feeling occurs when the dorsal thalamus is stimulated. In this theory, physiological changes and emotional experiences take place at the same time.
Answer:
eight oxygen atoms
Explanation:
This formula shows that in one mole of this compound, there are 3 moles of Ca atoms that combine with 2 moles of the PO4(phosphate) groups, which gives a total of 2 moles of P atoms and 8 moles of 0 atoms.
Answer:
pH = 4.27. Porcentaje de disociación: 0.03%
Explanation:
El pH de un ácido débil, HX, se obtiene haciendo uso de su equilibrio:
HX(aq) ⇄ H⁺(aq) + X⁻(aq)
Donde la constante de equilibrio, Ka, es
Ka = 1.65x10⁻⁸ = [H⁺] [X⁻] / [HX]
Como los iones H⁺ y X⁻ vienen del mismo equilibrio podemos decir:
[H⁺] = [X⁻]
[HX] es:
20g * (1mol/55g) = 0.3636moles / 2.100L = 0.1732M
Reemplazando es Ka:
1.65x10⁻⁸ = [H⁺] [H⁺] / [0.1732M]
2.858x10⁻⁹ = [H⁺]²
5.35x10⁻⁵M = [H⁺]
pH = -log[H⁺]
<h3>pH = 4.27</h3>
El porcentaje de disociacion es [X⁻] / [HX] inicial * 100
Reemplazando
5.35x10⁻⁵M / 0.1732M * 100
<h3>0.03%</h3>
