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Mashutka [201]
4 years ago
6

How many magnesium ions are present in 5.36 x 10-4 mol of magnesium iodide?

Chemistry
1 answer:
WARRIOR [948]4 years ago
4 0
Magnesium iodide = MgI₂
mass of Mg = 24.3g
mass of I = 126.9g
mass of MgI₂ = 24.3 + 2*126.9 = 278.1g = 1 mole

in 5.36x10⁻⁴ mole of MgI₂ ---------------- x g of Mg
in 1 mole of MgI₂ ------------------------------ 1 mole of Mg
x = 5.36x10⁻⁴ moles of Mg = 0.000536 moles of Mg

answer: we've 0.000536 moles of Mg (magnesium ions) in 5.36x10⁻⁴ moles of MgI₂

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Answer:

A) H2O > HCCH > NH3 > CH3CH3

Explanation:

H2O is known as a neural compound which a pH close to 7.0. This however makes it more acidic due to it having the lowest pH when compared to the others in the option.

The other options however have their acidic strength as follows: HCCH > NH3 > CH3CH3. This explains why the pattern of decreasing acidic strength is H2O > HCCH > NH3 > CH3CH3

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7 0
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When the reactive alkali metal sodium is reacted with poisonous chlorine gas, sodium chloride or table salt is produced. Is mass
PIT_PIT [208]

Answer:

Yes, Mass is conserved.

Explanation:

Every chemical reactions obey the law of conservation of mass. The law of conservation of mass states that in chemical reactions, mass is always constant.

     Equation:

                       2Na + Cl₂  →  2NaCl

From the equation above, one can observe that the reaction started using 2 atoms of Na and it produced 2 atoms of the same element in NaCl. A molecule of Cl produced 2 atoms of Cl in the NaCl

Design a simple experiment to support your answer:

Aim: To demonstrate the law of conservation of mass

   One Na atom weighs 23g

   Two Na atom will weigh 2 x 23 = 46g

1 atom of Cl is 35.5g

1 molecule of Cl containing two atoms of Cl will weigh 2 x 35.5 = 71g

Total mass of reactants = mass of 2Na + 1Cl₂ = (46 + 71)g = 117g

On the product side, Mass of 1 NaCl = 23+ 35.5 = 58.5g

Two moles of NaCl will give 2 x 58.5g = 117g

Since the mass on both side is the same, one can say mass is conserved.

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3 years ago
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a chemist dissolves 0.564 moles of manganese (IV) oxide (MnO2) in water, and adds enough water to make 0.510 L of solution. Calc
ladessa [460]

Answer:

The molarity of the solution is 1.1 \frac{moles}{liter}

Explanation:

Molarity is a measure of the concentration of that substance that is defined as the number of moles of solute divided by the volume of the solution.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

molarity=\frac{number of moles of solute}{volume}

Molarity is expressed in units \frac{moles}{liter}

In this case

  • number of moles of solute= 0.564 moles
  • volume= 0.510 L

Replacing:

molarity=\frac{0.564 moles}{0.510 L}

Solving:

molarity= 1.1 \frac{moles}{liter}

<u><em>The molarity of the solution is 1.1 </em></u>\frac{moles}{liter}<u><em></em></u>

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