Answer:
A.Glycogenesis: Glycogen synthase
B. Glucogenesis: Fructose 1,6 biphosphate phosphatase
C. Urea cycle : Carbamoyl phosphate synthetase
D.Fatty acid synthesis: Acetyl CoA carboxylase
E.Glycolysis : Phosphofructokinase 1
F. Pentose phosphate pathway: Glucose-6-phosphate dehydrogenase
Explanation:
A. Glycogen synthase converts glucose into glycogen during glycogenesis.
B. Fructose 1,6 biphosphate phosphatase catalyzes condensation of dihydroxyacetone phosphate (DHAP) and glyceraldehyde-3-phosphate during glucogenesis.
C. Carbamoyl phosphate synthetase I catalyses production of arbamoyl phosphate during urea cycle.
D. Carboxylase controls fatty acid metabolism.
E. The phosphofructokinase 1 is an important enzyme that regulate formation of two-phosphate sugar molecules during glycolysis.
F. Glucose-6-phosphate dehydrogenase participates in the pentose phosphate pathway. This pathway gives reducing energy to cells.
A cell that has DNA suspended in cytoplasm and not a nucleus is most likely a prokaryote, which have small DNA clusters called nucleoids
Answer: Loess is the fine grained material that has been transported and deposited by the wind. The answer is <u>A.</u>
Explanation:
Since the wind can carry these types of material (find grained) father than sand, and also higher up, they are generally found very far from their original place of origin.
Loess is no larger than 50 micrometers in size. It is coarse in texture like clay, but finer than a grain of salt.
The answer is greater omentum. The omentum is a membranous twofold layer of greasy tissue that spreads and backings the digestion tracts and organs in the lower stomach zone. The omentum is comprised of the more prominent omentum which is a vital stockpiling for fat stores and the lesser omentum which associate the stomach and digestion tracts to the liver.
There is 20 chromosomes in a adult wild mouse
