∠A is called inscribed angle. Inscribed angle is made from a point that attaches to the circle's circumference.
∠BOC is central angle. ∠BOC and ∠A are facing to the same side and because they are facing to the same side, they apply the rule of
inscribed angle = 1/2 × central angle
So we can find ∠A with this property
∠A = 1/2 × 132°
∠A = 66°
Which table? I’ll answer you in the comments
Answer:
Step-by-step explanation:
You need to pay very close attention to the triangle similarity statement. This says that triangle NML is similar to triangle NVU. But if you look at the way that triangle NVU is oriented in its appearance, it's laying on its side. We need to set it upright so that angle N is the vertex angle, angle V is the base angle on the left, and angle U is the base angle on the right. When we do that we see that sides NV and NM are corresponding and exist in a ratio to one another; likewise with sides VU and ML. Setting up the proportion:

Filling in:

Cross multiply to get
324 = 108x
and x = 3
The center is (-8, -3)
the radius is 2.5
hope that helps, God bless!
Half the length of the curve which separates the 2 halves = 1/2 circumference of a circle with diameter 6 mm. = 1/2 * pi * d = 3pi mm
So the length of the line = 6pi = 18.85 mm to nearest hundredth. answer
The area of shaded region = 1/2 area of the circle = 1/2 pi r^2
= 1/2 * pi * 6^2
= 56.55 mm^2 to nearest hundredth answer