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4 years ago

Which number represents 50% of 74? 35 37 38 39

Mathematics

2 answers:

zheka24 [161]4 years ago

6 0

Answer:

B) 37

Step-by-step explanation:

50% of 74 is 37.

oksian1 [2.3K]4 years ago

3 0

35 or 37 represent 50% of 74

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Please help me!!!!!!!

chubhunter [2.5K]

9514 1404 393

Answer:

y = -4x +2

Step-by-step explanation:

The equation you're writing is in slope-intercept form. The coefficient of x is the slope, which is the "rise"/"run" of the line.

Here, to get from the left point to the right point, you must go down 4 units (rise=-4) and 1 unit to the right (run=1). So, the slope is ...

m = rise/run = -4/1 = -4

The constant in the equation is the y-intercept: the y-coordinate of the point where the line crosses the y-axis. That point is marked as (0, 2), so its y-coordinate is 2.

The equation for the line is ...

y = -4x +2

8 0

3 years ago

What is the volume of the cuboid in cm3 ? What is the volume of the cuboid in mm3

KengaRu [80]

Answer:

3150mm

Step-by-step explanation:

1cm is 10mm you convert it then times it together l x b x h will equal 3150

7 0

1 year ago

The graph of y = x^2 is translated 3 units to the left. The equation for this new graph is:

EastWind [94]

The answer is:
C. Y=(x+3)^2

7 0

3 years ago

Show work and factor ?

kvasek [131]

$5\cdot\dfrac{x^2-2x}{6}:\dfrac{3x-6}{x}=5\cdot\dfrac{x(x-2)}{6}\cdot\dfrac{x}{3x-6}\\\\=5\cdot\dfrac{x(x-2)}{6}\cdot\dfrac{x}{3(x-2)}=\dfrac{5\cdot x\cdot x}{6\cdot3}=\dfrac{5x^2}{18}$

4 0

3 years ago

F(x) = e^-x . Find the equation of the tangent to f(x) at x=-1

natima [27]

Answer:

The equation of the tangent line is given by the following equation:

$\displaystyle y - \frac{1}{e} = \frac{-1}{e} \bigg( x - 1 \bigg)$

General Formulas and Concepts:

Algebra I

Point-Slope Form: y - y₁ = m(x - x₁)

x₁ - x coordinate
y₁ - y coordinate
m - slope

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]:
$\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:
$\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

*Note:

Recall that the definition of the derivative is the slope of the tangent line.

Step 1: Define

Identify given.

$\displaystylef(x) = e^{-x} \\x = -1$

Step 2: Differentiate

[Function] Apply Exponential Differentiation [Derivative Rule - Chain Rule]:
$\displaystyle f'(x) = e^{-x}(-x)'$
[Derivative] Rewrite [Derivative Rule - Multiplied Constant]:
$\displaystyle f'(x) = -e^{-x}(x)'$
[Derivative] Apply Derivative Rule [Derivative Rule - Basic Power Rule]:
$\displaystyle f'(x) = -e^{-x}$