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Snezhnost [94]
4 years ago
15

Which number represents 50% of 74? 35 37 38 39

Mathematics
2 answers:
zheka24 [161]4 years ago
6 0

Answer:

B) 37

Step-by-step explanation:

50% of 74 is 37.

oksian1 [2.3K]4 years ago
3 0
35 or 37 represent 50% of 74
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I need help with this
Finger [1]

ask your teacher.

use a calculator.

Use math tutoring for this module.

Pay more attention to the lecture.

3 0
3 years ago
If ST≅SV and m∠SUT=68°, what is m∠TUV?
artcher [175]

Answer:

136

Step-by-step explanation:

Take 68 x 2 since the side lengths are equal.

6 0
3 years ago
Find the value of y in parallelogram QRST.
Arturiano [62]
<h2>Answer:</h2>

y = 5

<h2>Step-by-step explanation:</h2>

<em>Solution:</em>

7y = 5y + 10

7y - 5y = 10

2y = 10

\frac{2y}{2} = \frac{10}{2}

y = 5

<em>Checking:</em>

7y - 5y = 10

7(5) - 5(5) = 10

35 - 25 = 10 ✓

<h2>#Brainliest</h2><h2>#CarryOnLearning</h2>
5 0
3 years ago
Read 2 more answers
If we add two equations in the original system, we have 6x+7y=32. Explain why the same (x,y) pair is also a solution to the equa
Fynjy0 [20]

Answer:

simultaneous equations are used to solve for 2 variable

8 0
2 years ago
A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p
Alekssandra [29.7K]

Using the z-distribution and the formula for the margin of error, it is found that:

a) A sample size of 54 is needed.

b) A sample size of 752 is needed.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which z is the z-score that has a p-value of \frac{1+\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level, hence\alpha = 0.9, z is the value of Z that has a p-value of \frac{1+0.9}{2} = 0.95, so z = 1.645.

Item a:

The estimate is \pi = 0.213 - 0.195 = 0.018.

The sample size is <u>n for which M = 0.03</u>, hence:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.018(0.982)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.018(0.982)}

\sqrt{n} = \frac{1.645\sqrt{0.018(0.982)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.018(0.982)}}{0.03}\right)^2

n = 53.1

Rounding up, a sample size of 54 is needed.

Item b:

No prior estimate, hence \pi = 0.05

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.5(0.5)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.5(0.5)}

\sqrt{n} = \frac{1.645\sqrt{0.5(0.5)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.5(0.5)}}{0.03}\right)^2

n = 751.7

Rounding up, a sample of 752 should be taken.

A similar problem is given at brainly.com/question/25694087

5 0
3 years ago
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