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MAVERICK [17]
3 years ago
8

(x+4)(x-2) as a triomial in standard form

Mathematics
2 answers:
ZanzabumX [31]3 years ago
7 0

x^2 + 2x - 8

just multiply (x+4)(x-2)

x times x = x^2

x times -2 = -2x

4 times x = 4x

4 times -2 = -8

-2x + 4x = 2x

Nataliya [291]3 years ago
6 0

Answer:

x² - 8x + 16 Hope this helps

Step-by-step explanation:

Step 1: Write out expression

(x - 4)²

Step 2: Expand

(x - 4)(x - 4)

Step 3: FOIL

x² - 4x - 4x + 16

Step 4: Combine like terms

x² - 8x + 16

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What is the area of a shape with points a 5 -8 b 11, -8 c 11,0 d 6,-3 e 4,-3
Dmitriy789 [7]

Answer:

Area of the given figure is 51.5 square units.

Step-by-step explanation:

Area of rectangle OCBH = Length × width

                                         = 11 × 8

                                         = 88 square units

Area of trapezoid OGEF = \frac{1}{2}(b_1+b_2)\times h

                                         = \frac{1}{2}(\text{GE+OF)}\times (\text{OG})

                                         = \frac{1}{2}(3+6)\times 4

                                         = 18 units²

Area of trapezoid GCDE = \frac{1}{2}(\text{GC+DE)}\times (\text{GE})

                                         = \frac{1}{2}(7+2)\times 3

                                         = 13.5 units²

Area of triangle AFH = \frac{1}{2}(\text{Base})\times (\text{Height})

                                  = \frac{1}{2}(5)(2)

                                  = 5 units²

Area of polygon ABCDEF = Area of rectangle CBHO - (Area of trapezoid OGEF + Area of trapezoid GCDE + Area of triangle AFH)

                                           = 88 - (18 + 13.5 + 5)

                                           = 88 - 36.5

                                           = 51.5 units²

Therefore, area of the given polygon is 51.5 units²

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