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icang [17]
3 years ago
11

George has a mass of 65kg. What would George weigh on the Moon? (The gravitational field strength on the Moon is 1.6N/kg.)

Mathematics
2 answers:
zubka84 [21]3 years ago
7 0

Answer: Weight of George on Moon =104 N

Step-by-step explanation:

Given : George has a mass of 65 kg.

The gravitational field strength on the Moon is 1.6N/kg.

Then, the weight of George on Moon = George's Mass x Gravitational field strength

=65\times1.6=104\text{ Newtons}

Hence, the weight of George on Moon =104 N

maks197457 [2]3 years ago
3 0

George would weigh

65 kg × 1.6N /kg = 104 Newtons

That's compared to around 650 Newtons on earth.

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I think its missing info?
4 0
3 years ago
X + 3x² – 28x <br><br> Can you guys help me solve this in ax^2+bx+c <br> Thank you thank you
Molodets [167]

Answer:

3x²+(-27x) +0

Step-by-step explanation:

The given expression is :

x + 3x² – 28x

We need to solve this in the form of ax²+bx+c.

we can write the given expression as :

3x²-28x+x = 3x²-27x

= 3x²+(-27x) +0

If we compare the given expression with the general expression, we find that,

a = 3, b = -27 and c = 0

Hence, the required equation is 3x²+(-27x) +0.

3 0
2 years ago
Suppose j varies jointly with g and v, and j=1 when g=4 and v=5. what is j when g=10 and v=9?
Tems11 [23]
J\alpha gv
j=agv where a is a constant of proportionality.
j=1 when g=4 and v=5
1=a*4*5
1=20a
a=1/20
a= 0.05
j=0.05gv
When g=10 and v=9,
j=0.05*10*9
j=0.5*9
j=4.5
4 0
3 years ago
What is the Compound interest on a 10,000 investment the earns 6% compound monthlyfor5 years
Vlad1618 [11]

Answer:

The total compound interest is $3,488.50, I hope I helped explain how to find total compound interest

Step-by-step explanation:

So the formula for this would be:

A = P(1+r/n)^nt

A = the amount of your principal plus interest, which is the total

P = stands for the principal, which is your original amount invested

r = shows the interest rate in decimal form

n =  stands for the number of compounding periods

So to solve for the compound interest we would plug in our numbers in replacement for the letters

8 0
2 years ago
Find four consecutive even integers such that seven times the first exceeds their sum by 18.
Ganezh [65]

Answer:

10, 12, 14, 16

Step-by-step explanation:

Given: Four consecutive even integers such that seven times the first exceeds their sum by 18.

Lets assume the first number be "x".

As it is even integers

∴ Second consecutive number will be (x+2)

  Third consecutive number will be (x+4)

  Fourth consecutive number will be (x+6)

Now, as given seven times the first exceeds their sum by 18.

∴ [x+(x+2)+(x+4)+(x+6)]+18 = 7x

solving the equation to find the number.

⇒ [x+(x+2)+(x+4)+(x+6)]+18 = 7x

Opening parenthesis

x+x+2+x+4+x+6+18 = 7x

⇒ 4x+30= 7x

subtracting both side by 4x

⇒ 30= 3x

Dividing both side by 3

∴ x= 10.

Hence, subtituting the value x to find four consecutive even integers.

  First number is 10

  Second consecutive number will be (10+2) = 12

  Third consecutive number will be (10+4)= 14

  Fourth consecutive number will be (10+6) = 16

∴ Four consecutive even integers are 10,12,14,16.

8 0
3 years ago
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