What is the nth term rule of the quadratic sequence below /-7, -4, 3, 14, 29, 48, 71
1 answer:
Answer:
nth term = 2n^2 - 3n - 6.
Step-by-step explanation:
n = 1 2 3 4 5 6 7
- 7 -4 3 14 29 48 71
Differences 3 7 11 15 19 23
Differences 4 4 4 4 4
So the first term in the Rule is 2n^2
Subtracting the values of 2n^2 from the original terms:
- 7 -4 3 14 29 48 71
2n^2 2 8 18 32 50 72 98
Subtrct -9 -12 -15 -18 -21 -24 -27
-3 -3 -3 -3 -3 -3
So we have -3n and the last term is -6 because -7 = 2(1)^2 -3 - 6 and the other terms fit this pattern as well.
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