Answer:
53
Step-by-step explanation:
1) Take the area of the rectangle from origin to Point B. We see that it is 8 * 11 = 88 units of area
2) We subtract all the triangles in the rectangle that are not covered by the shape.
So
- Triangle FAPoint(0,-8) area = 1/2 * 2 * 5 = 5
- Triangle FEPoint(0,-3) area = 1/2 * 3 * 4 = 6
- Rectangle P(0,0) P(0,-3) P(6,-3) P(6,0) area = 6 * 3 = 18
- Triangle DP(6,0)P(11,0) area = 1/2 * 5 * 3 = 7.5
Take the area of the big imaginary rectangle and subtract the area of all the smaller triangles and the smaller rectangle
88 - 5 - 6 - 7.5 - 18 = 51.5
Done!
Answer:
The word "ARRANGE" can be arranged in
2!×2!
7!
=
4
5040
=1260 ways.
For the two R's do occur together, let us make a group of R's taking from "ARRANGE" and permute them.
Then the number of ways =
2!
6!
=360.
The number ways to arrange "ARRANGE", where two "R's" will not occur together is =1260−360=900.
Also in the same way, the number of ways where two "A's" are together is 360.
The number of ways where two "A's" and two "R's" are together is 5!=120.
The number of ways where neither two "A's" nor two "R's" are together is =1260−(360+360)+120=660.
Step-by-step explanation:
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So based on your question about the line A and B meet and the four lines are congruent to each other. The graph doesnt show any measurements so there is no exact value to the length of X. But you must consider that the lines are proportional to each other so it means that they are congruent.
