490
Step-by-step explanation:
4333333
67
8
Answer:
False
Step-by-step explanation:
Consider the equations with the same number of equations and variables as shown below,
<u>Case 1</u>

This equation has no solution because it is not possible to have two numbers that give a sum of 0 and 1 simultaneously.
<u>Case 2</u>

This equation has infinitely many possible solutions.
Therefore it is FALSE to say a linear system with the same number of equations and variables, must have a unique solution.
85a
<span>2-b=c -(13-b)=c2-b=-13+b2b=15b=15/2c=2-15/2=4/2-15/2=-11/2 C cannot be negative, so 2-b not >0 and 13-b not <0
Both 2-b and 13-b cannot be both positive and negative, because 2-b=13-b is wrong
-(2-b)=c, 13-b=c, -2+b=13-b, 2b=15, b=15/2, c=13-b=13-15/2=26/2-15/2=11/2So, finally b=15/2 and c=11/2Answer is abs(x-15/2)=11/2
</span>
I believe the answer would be 4 but I don’t see the graph I tries to make one but that didn’t work out lol
Line 3:
if 2cm is the same as 15 miles, then 1cm is 7.5 miles.
This implies that 16.27cm are the same as
miles
Line 4:
if 1/2cm is the same as 20 miles, then 1cm is 40 miles.
This implies that 11.73cm are the same as
miles